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3 years ago

What is the sentence of totipotent?

Biology

1 answer:

Pani-rosa [81]3 years ago

4 0

Answer:

Explanation:

What are the options

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Which type of succession do the biotic components of a community cause?

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Primary succession, while secondary is caused by a natural disaster

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3 years ago

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Write a report based on a news article wherein a court convicted an individual based on DNA evidence years after the crime took

horrorfan [7]

DNA testing can be used to identify samples from different persons by matching the linear order of nucleotides.

<h3>What is DNA testing?</h3>

DNA testing refers to the genetic approaches and technologies used in the investigation to match different DNA samples.

DNA testing is a very useful approach for identifying individuals and inferring ancestry in evolutionary studies.

In conclusion, DNA testing can be used to identify samples from different persons by matching the linear order of nucleotides.

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2 years ago

In gorillas, the ability to roll the tongue is under the control of 1 gene. The R allele, which confers tongue-rolling ability,

aalyn [17]

Answer:

0.4550

Explanation:

In this example, R allele is dominant, so individuals RR and Rr can roll their tongues. If in a population of 1000 gorillas, there are 575 gorillas who can roll their tongues, they will be RR and Rr.

In this case, there is Hardy Weinberg Equilibrium, so the following will be true:

$p^{2}+2pq+q^{2}=1$

Where:

$p^{2}=$ frequency of RR

$2pq=$ frequency of Rr

$q^{2}=$ frequency of rr

The question is what is the frequency of heterozygotes, or, what is the value of 2pq.

We know that RR+Rr is 575 individuals in a population of 1000, or 0.575.

In other words:

$p^{2}+2pq=0.575$

So, it is possible to find $q^{2}$ :

$q^{2}= 1-2pq-p^{2} \\q^{2}=1-(0.575)\\q^{2}=0.425$

Now, there are two alleles in the population, so the following will be true:

$p+q=1$

It is possible to find q (the frequency of allele r) and p (the frequency of allele p):

$q=\sqrt{q^{2} }\\ q=\sqrt{0.425} \\q=0.652$

Therefore:

$p=1-q\\p=1-0.652\\p=0.348$

Now, the frequency of heterozygotes or 2pq is:

$2pq=2*0.652*0.348\\2pq=0.45$

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3 years ago

I’ll give extra points for who ever does this

alex41 [277]

You see this is correct because

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3 years ago

Oi! Bakugo here. I need some help again.

pishuonlain [190]

The decrease in reproductive function.

Explanation:

For a couple attempting to have a child, having at least two miscarriages may be a sign of an chromosomal abnormality.

Hi btw

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3 years ago