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masya89 [10]
3 years ago
5

A Robotics Club has 16 members. Each member pay monthly dues of $14.60. On the first day of the month 10 members paid their dues

. The remaining members paid their dues on the second day of the month. How much money was collected on the second day of the month?
Mathematics
1 answer:
Vitek1552 [10]3 years ago
7 0

Answer:

Total cash collected= $87.6

Step-by-step explanation:

Giving the following information:

A Robotics Club has 16 members. Each member pay monthly dues of $14.60. On the first day of the month 10 members paid their dues.

<u>To calculate the total cash collected on the second day, we need to use the following formula:</u>

Total cash collected= unitary cost*number of members

Total cash collected= 14.6*6

Total cash collected= $87.6

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klemol [59]
12.195+9.13=21.325 is the answer
5 0
4 years ago
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In a study of 799 randomly selected medical malpractice​ lawsuits, it was found that 499 of them were dropped or dismissed. Use
Mademuasel [1]

Answer:

Claim is true that most medical malpractice lawsuits are dropped or dismissed.

Step-by-step explanation:

Given :In a study of 799 randomly selected medical malpractice​ lawsuits, it was found that 499 of them were dropped or dismissed.

To Find : Use a 0.05 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed.

Solution:

n =  799

x = 499

We will use one sample proportion test  

\widehat{p}=\frac{x}{n}\\\widehat{p}=\frac{499 }{ 799}\\\widehat{p}=0.6245

We are given that the claim is most medical malpractice lawsuits are dropped or dismissed.

Probability of dropped or dismissed is 1/2

 H_0:p=0.5\\H_a:p>0.5

Formula of test statistic = \frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

                                        =\frac{0.6245-0.5}{\sqrt{\frac{0.5(1-0.5)}{799}}}

                                       = 7.038

p value (z>7.038) is 0

α =0.05

So, p value < α

So, we reject the null hypothesis

So,claim is true

Hence most medical malpractice lawsuits are dropped or dismissed.

6 0
3 years ago
At the souvenir shop. Theo buys k key chains and p photo frames
stealth61 [152]

Answer:

Total cost of Theo's purchases in terms of k and p=2.49(k + p) + 5.99

Step-by-step explanation:

Cost of k key chain=$2.49

Cost of p photo frames=$2.49

Cost of a T-shirt=$5.99

Total cost of all items=cost of k key chain + cost of p photo frame + cost of The shirt

=2.49k + 2.49p + 5.99

Factorise

2.49 is common to both k and p

=2.49(k + p) + 5.99

Total cost of Theo's purchases in terms of k and p=2.49(k + p) + 5.99

4 0
3 years ago
Mrs. Torres’s class has 28 students. The class includes 12 boys. What is the
Maslowich

Answer:

16:12 or 4:3

Step-by-step explanation:

Girls + boys = 28

Girls + 12 = 28

Girls = 16

Girls to boys:

16:12

16/12

4:3

6 0
3 years ago
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Evaluate 6²-7²+8²-9²+..+998²-999²​
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Answer:

-499,485.

Step-by-step explanation:

We can transform this to an arithmetic series by  working it out in pairs:

6^2 - 7^2 = (6-7)(6+7) = -13

8^2 - 9^2 = (8-9)*8+9) = -17  

10^2 - 11^2 = -1 * 21 = -21 and so on

The common difference is -4.

The number of terms in this series  is (998 - 6) / 2 + 1

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Sum of n terms of an A.S:

= n/2 [2a1 + (n - 1)d  

Here a1 = -13, n = 497, d = -4:

Sum = (497/2)[-26 - 4(497-1)]

= 497/2 * -2010

= -499,485.

3 0
3 years ago
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