<span>sin x + cos x = l would be the answer</span>
Step-by-step explanation:
y = x - 4 and y = 4x + 2
=> x - 4 = 4x + 2
=> 3x = -6
=> x = -2
y = x - 4 = (-2) - 4 = -6
The solutions are x = -2 and y = -6.
Negative since the answer would be -13
Answer: a) Mean = 5, Median = 5
b) Mean = 15, Median = 5
c) Due to presence of outlier i.e. 99.
Step-by-step explanation:
Since we have given that
1,2,3,4,5,6,7,8,9
Here, n = 9 which is odd
So, Mean would be

Median = 
If 9 is replaced by 99,
1,2,3,4,5,6,7,8,99
So, mean would be

Median would be same as before i.e. 5
The mean is neither central nor typical for the data due to outlier i.e. 99
Hence, a) Mean = 5, Median = 5
b) Mean = 15, Median = 5
c) Due to presence of outlier i.e. 99.
1,0,10,7,13,2,9,15,0,3/ 10
=60/10
=6