Answer:
By AA similarity
Step-by-step explanation:
We have been given that ABCD is a parallelogram
So, by the property of parallelogram AB ||CD and FD is cutting the line BC
Hence, FD is transverse line. In transverse line alternate angles are equal.
Therefore, ∠AFD=∠EDC (alternate interior angles)
And ∠FAD=∠ECD (opposite angles in parallelogram)
Therefore, by AA similarity △ADF∼△CDE
Question below!
what do you need in order to construct in order to find a point/location that has the same distance away from 2 or more other points
Answer:
Hi, There! Mika-Chan I'm here to help! :)
<u><em>To find the distance from a point to a line, first find the perpendicular line passing through the point. Then using the Pythagorean theorem, find the distance from the original point to the point of intersection between the two lines.</em></u>
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<u><em>Hope this Helps!</em></u>
1.) - sqrt. 2 (which, in decimal, is about -1.4142…) , 0, sqrt. 5 (which, in decimal, is about 2.2360…) , 13/4
2.) -1.5, 3/4 (which, in decimal, is 0.75) , 3, sqrt 10 (which, in decimal, is about 3.1622…)
3.) -3/2 (which, in decimal, is -1.5), -3/7 (which, in decimal, is about -0.4285…) , 0.75, 2
