The applicable formula is;
A = P(1+r)^nt
Where
A = Accumulate amount
P = Initial invested amount
r = Annual interest rate
n = Number of payments in a year
t = Time in years
First part of the question: Accumulated amount after 18 years
Substituting;
A = 1000(1+0.01)^12*18 = $8,578.61
Since the car costs $15,000 and the amount in the bank after 18 years is $8,578.61, Anthony wouldn't be able to afford the car.
Second part of the question: The amount which should have been deposited for Antony to afford the car after 18 years
15,000 = P (1+0.01)^12*18
15,000 = P*8.5786
P = 15,000/8.5786 = $1,748.54
Therefore, for Antony to afford the $15,000 after 18 years, the mum should have deposited $1,748.54.
Answer:
be itshwhehehee such brush hahbshkd
Answer:
1) Slope of the line 
2)Slope of the line m = 2
3) slope of the line m = -5
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that equation of the straight line 3 x+2 y =0
The slope - intercept form y = mx +c
2 y = - 3x
Slope of the line 
<u><em>Step(ii):-</em></u>
Given that equation of the straight line 2 x- y = 3
The slope - intercept form y = mx +c
y = 2x -3
slope of the line m = 2
<u><em>Step(iii):-</em></u>
Given that equation of the straight line 5 x + y = 10
The slope - intercept form y = mx +c
y = -5x +10
slope of the line m = -5
Answer:
2x+1
2x-1
2x+4
2x-4
Step-by-step explanation:
Answer:
p(4)=4^2-5(4)
P(4)=16-20
P(4)=4
Step-by-step explanation: