Let the equal sides of the isosceles Δ ABC be x.
Given that the perimeter of Δ ABC = 50m.
Therefore, 2x + AC = 50 --- (1)
It is also given that the perimeter of Δ ABD = 40m.
Therefore, x + BD + AD = 40
BD is the median of the Δ ABC. Therefore, D is the midpoint of AC.
So AD = CD.
Or, AD = 
AC
Therefore, 
Multiply both sides by 2.
2x + 2BD + AC = 80
From (1), 2x + AC = 50.
Therefore, 2BD + 50 = 80
2BD = 80 - 50
2BD = 30
BD = 15m.
The total weight of Mason is 177
<em><u>Solution:</u></em>
Given that, Mr.Mason takes two-thirds of his body weight and drinks that amount of gatorade in ounces per day
Mr.Mason drinks 118 ounces each day
Let "x" be the total weight of Mr.Mason
Therefore, we can say,
Two third of body weight = Amount of gatorade drank in ounces per day
Two third of x = 118
Thus total weight of Mason is 177
Answer:
SAS
Step-by-step explanation:
We must prove that triangles ABC and EDC are congruent.
Since BD bisects AE, then AC is congruent with CE.
Since AE bisects BD, then BC is congruent with CD
Angle C is 90° in the triangle EDC and is also 90° in triangle BCA because they are vertical angles.
Being two sides and the included angle congruent, then both triangles are similar by the SAS theorem.
Answer: SAS
I’m not really sure but I would say c
Answer:
y = 3x
Step-by-step explanation:
Given
9x - y = - 6x + 4y ( subtract 4y from both sides )
9x - 5y = - 6x ( subtract 9x from both sides )
- 5y = - 15x ( divide both sides by - 5 )
y = 3x
