We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.
Since these are different, this is not linear.
We now find the second differences:
5-3=2; 7-5=2; 9-7=2. Then:
Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².
We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.
Now we find the difference between the actual terms of the sequence and the numbers we just found:
4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.
Since this is constant, the sequence is in the form (1/2a)n²+d;
in our case, 1n²+d, and since d=3, 1n²+3.
The correct answer is n²+3
Answer:
0.84
Step-by-step explanation:
Given that Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are summarized as follows:
P(A) = 0.86, P(B) = 0.79, P(A') = 0.14, P(AUB) = 0.95
We are to find out P(A'UB)
We have
![P(A'UB) = P(A')+P(B)-P(A' \bigcap B)\\= 1-P(A) +P(B)-[P(B)-P(A \bigcap B)]\\= 1-0.86+0.79-P(B)+[tex]P(A'UB)=0.14+0.79-0.79+0.70\\=0.84](https://tex.z-dn.net/?f=P%28A%27UB%29%20%3D%20P%28A%27%29%2BP%28B%29-P%28A%27%20%5Cbigcap%20B%29%5C%5C%3D%201-P%28A%29%20%2BP%28B%29-%5BP%28B%29-P%28A%20%5Cbigcap%20B%29%5D%5C%5C%3D%201-0.86%2B0.79-P%28B%29%2B%5Btex%5DP%28A%27UB%29%3D0.14%2B0.79-0.79%2B0.70%5C%5C%3D0.84)
P(A \bigcap B)[/tex]
(x + 1) x (x - 4). When you check it you will get your original expression.
Answer: (a) x + 2y = -1 and 3x + y = 1
<u>Step-by-step explanation:</u>
I am not sure what the purpose was for the colored lines but I included them on the graph (below).
Multiply by z to get
wz = xy
divide by x
y = wz/x
