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ryzh [129]
3 years ago
8

Help please thank you

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
4 0

Answer:

0.25

Step-by-step explanation:

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The value of the pronumeral​
Sergio039 [100]

Answer: stop pay attention in class

Step-by-step explanation:

7 0
3 years ago
What is the decimal that is 1/10 of 3.0
Musya8 [376]

the answer to that is 2.9 because 3.0-0.1=2.9


3 0
3 years ago
Read 2 more answers
In the diagram, how many angles are alternate exterior angles with angle 5?
Natasha_Volkova [10]

Answer:

Angle 11 is the alternate exterior of angle 5 meaning there is only 1 angle that is alternate of angle 5.

Step-by-step explanation:

An exterior angle is an angle outside of the shape (hence ex meaning out). However, an ALTERNATE angle is an angle opposite of a transversal line of another angle. The angles on the same transversal line of 5 are 8, 7, 9, 10, 12, and 11. However, we are looking for ALTERNATE EXTERIOR angles not just exterior. 8, 7, 9, 10, and 12 are just exterior which leaves angle 11 as alternate exterior. Angle 11 is the alternate exterior of angle 5 meaning there is only 1 angle that is alternate of angle 5.

4 0
3 years ago
Solve this please, and quick
rosijanka [135]
Error: They subtracted 9x from both sides when they should have subtracted 12. You can’t subtract unlike terms
Correct: x=-5/16
Subtract 12 from both sides to get -5 on the left and add 7x and 9x to get 16x. Divide both sides by 16 to isolate x.
8 0
3 years ago
Read 2 more answers
Solve for each system of equations by substitution or elimination.
Tems11 [23]

QUESTION 1

The given system of equations are:

y=x^2+5x+1

y=x^2+2x+1

We equate the two equations to get:

x^2+5x+1 =x^2+2x+1

x^2 -  {x}^{2} + 5x  - 2x = 1 - 1

3x = 0

x = 0

When x=0,

y=0^2+2(0)+1 = 1

The solution is (0,1)

QUESTION 2

The given equations are:

y=x^2-2x - 1

and

y= -x^2-2x-1

We equate both equations to get:

x^2-2x - 1 = -x^2-2x-1

Group similar terms,

x^2 +  {x}^{2} -2x  + 2x= -1 + 1

2 {x}^{2}  = 0

x = 0

We put x=0 into any of the equations to find y.

y= -0^2-2(0)-1 =  - 1

The solution is (0,-1).

QUESTION 3

The given equations are:

y=x^2+2x+1

and

y=x^2+2x-1

We equate both equations:

x^2+2x+1 = x^2+2x-1

Group similar terms:

x^2 -x^2+2x = -1 - 1

0 =  -2

This is not true.

Hence the system has no solution.

6 0
3 years ago
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