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3 years ago

8

Help please thank you

1 answer:

Sergeeva-Olga [200]3 years ago

4 0

Answer:

0.25

Step-by-step explanation:

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Can someone help me with this please? I will mark you brainliest

lina2011 [118]

Answer:

On the vertical axis, place frequencies. Label this axis "Frequency".

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Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vvOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vcOn the vertical axis, place frequencies. Label this axis "Frequency".

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Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Step-by-step explanation:

6 0

2 years ago

If MO=7x−4, and NO=6x, what is the length of MN¯¯¯¯¯¯¯¯¯¯?

mixas84 [53]

Answer:

13x-4

Step-by-step explanation:

MO=7x-4

NO=6x

MO+NO=?

7x-4+6x=13x-4

7 0

3 years ago

Read 2 more answers

I don't know how to simplify

In-s [12.5K]

(5-2/x)/4-3/x^2

after simplifying these
(5x-2)/x(4x^2-3)/x^2
x(5x-2)/(4x^2-3)
5x^2-2x/4x^2-3

now u can solve it

6 0

3 years ago

Making coconut cookies. The recipe calls for 420 g of coconut and 120 g of sugar. Only has 252 g of coconut. How much sugar must

geniusboy [140]

Answer: 72 grams.

Step-by-step explanation:

Let be "s" the amount of sugar in grams that must be used for 252 grams of coconut to keep the same ratio of coconut to sugar.

Knowing that in the recipe for the coconut cookies, should be 420 grams of coconut and 120 grams of sugar, and you only have 252 grams of coconut, you can set up this proportion to find "s":

$\frac{420grams}{120grams}=\frac{252grams}{s}$

Now, you need to solve for "s":

$\frac{420grams}{120grams}=\frac{252grams}{s}\\\\s(\frac{420grams}{120grams})=252grams\\\\s=(252grams)(\frac{120grams}{420grams})\\\\s=72grams$

4 0

3 years ago

A population of 1,000 squirrels lives on a rectangle-shaped farm plot that is 25 feet long by 10 feet wide what is the populatio

Lemur [1.5K]

First, find the area of the plot:
25*10=250

1000/250 is 4

the population density is 4 squirrels per square foot.

5 0

3 years ago