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3 years ago

Can somebody please help

Mathematics

2 answers:

Digiron [165]3 years ago

7 0

i honestly don't know :-l

Lynna [10]3 years ago

6 0

100 degrees :) hope this helps

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A jewelry store purchases necklaces for n dollars each. The necklaces are then marked up by 20%, and costumers are charged 5% sa

Aleksandr [31]

Answer:

Step-by-step explanation:

Cost price = $n

Mark up price = selling price- cost price

= (20% × $n)

Selling price = $n + (20% × $n)

Sales tax = 5% × ($n + (20% × $n))

Total cost = selling price + sales tax

Total cost = $n + (20% × $n) + 5% × $n + (20% × $n)

= 1.2 × $n + 0.06 × $n

= 1.26 × $n.

8 0

3 years ago

Round 832 to the nearest hundreds place.

elena-s [515]

Answer:

800

Step-by-step explanation:

Look at the tens if it's 0-4 keep the number the same if 5-9 go up one number

6 0

3 years ago

Read 2 more answers

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.

tatyana61 [14]

Answer:

(a) $g(n)=0.05\cdot 2^n$

(b) $g^{-1}(n)=\log_{2}20g(n)$

Step-by-step explanation:

Part A

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

$g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n$

Part B

$g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)$

Part C

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

$g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43$