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vlabodo [156]
3 years ago
7

The ball's height (in meters above the ground), xxx seconds after Antoine threw it, is modeled by: h(x)=-2x^2+4x+16 How many sec

onds after being thrown will the ball hit the ground? seconds
Mathematics
2 answers:
zlopas [31]3 years ago
5 0

Answer:

Step-by-step explanation:

If we are given the quadratic model, we know that the height of anything on the ground is 0 meters, so that model becomes

0=-2t^2+4t+16 I changed your x's to t's since t is for time.

Now we need to factor that quadratic and solve for time:

0=-2(t^2-2t-8)

Since -2 definitely does not equal 0, then

t^2-2t-8=0

Factor that and find t values of 4 and -2.  Again, we know that time will never be negative, so

t = 4 seconds.

stiks02 [169]3 years ago
3 0

Answer:

Answer is 16. Not 4.

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<u>x</u><u>=</u><u>3</u><u>6</u><u>°</u><u>,</u><u>y</u><u>=</u><u>2</u><u>5</u><u>°</u>

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