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vlabodo [156]
3 years ago
7

The ball's height (in meters above the ground), xxx seconds after Antoine threw it, is modeled by: h(x)=-2x^2+4x+16 How many sec

onds after being thrown will the ball hit the ground? seconds
Mathematics
2 answers:
zlopas [31]3 years ago
5 0

Answer:

Step-by-step explanation:

If we are given the quadratic model, we know that the height of anything on the ground is 0 meters, so that model becomes

0=-2t^2+4t+16 I changed your x's to t's since t is for time.

Now we need to factor that quadratic and solve for time:

0=-2(t^2-2t-8)

Since -2 definitely does not equal 0, then

t^2-2t-8=0

Factor that and find t values of 4 and -2.  Again, we know that time will never be negative, so

t = 4 seconds.

stiks02 [169]3 years ago
3 0

Answer:

Answer is 16. Not 4.

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Answer:

D. All of the above.

Step-by-step explanation: Please brainliest if correct!

7 0
3 years ago
1/2(4x-2)-2/3(6x+9) greater or equal to 4
Simora [160]
1/2(4x-2)-2/3(6x+9)
(2x-1)-(4x+6)
2x-1-4x+62x-4x-1+6
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So I believe that it is greater than 4
8 0
4 years ago
35 less than seven times a certain number is fifty-three more than 3 times that number. What is the number?
Dovator [93]

Answer:

70

Step-by-step explanation:

6 0
4 years ago
WILL MARK BRAINLIEST
Nutka1998 [239]

Answer:

a² + b² = 68

a3 + b3 = 520

Step-by-step explanation:

Given :

a + b = 10 (1)

ab = 16 (2)

A. Find a² + b²

(a + b)² = a² + 2ab + b² (3)

Substitutite the values of (1) and (2) into (3)

(10)² = a² + 2(16) + b²

100 = a² + 32 + b²

Subtract 32 from both sides

100 - 32 = a² + b²

a² + b² = 68

B. a^3 + b^3

(a + b)^3 = a^3 + b^3 + 3ab(a + b)

(10)^3 = a^3 + b^3 + 3*16(10)

1000 = a^3 + b^3 + 480

a^3 + b^3 = 1000 - 480

a3 + b3 = 520

5 0
3 years ago
PLEASE HELPPPPP
AnnyKZ [126]
An even prime number would be 4,8,10
3 0
3 years ago
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