A function for which every element of the range of the function corresponds to exactly one element of the domain. One-to-one is often written 1-1. Note: y = f(x) is a function if it passes the vertical line test.
Answer:
Step-by-step explanation:
We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).
First, recall that the equation of a circle is given by:
Where (<em>h, k</em>) is the center and <em>r</em> is the radius.
Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:
Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:
Solve for <em>r: </em>
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Simplify. Thus:
Finally, add:
We don't need to take the square root of both sides, as we will have the square it again anyways.
Therefore, our equation is:
The slope of an absolute function at the point where it evaluates to zero is undefined.
Here, when x=1, so |4x-4|=|4-4|=|0|, the slope is undefined. This is where the vertex of the "V" on the graph of the absolute value function.
The surface gravity of Mars is 3.7 m/s². On Earth it is 9.8 m/s². 3.7/9.8 = 38%.
So 38% of 120 lbs is 45 pounds.
Answer:
See below
Step-by-step explanation:
<u>Parent function:</u>
<u>Transformed function:</u>
- y = 4(3)⁻²ˣ⁺⁸ + 6, (note. I see this as 8, sorry if different but it doesn't make any change to transformation method)
<u>Transformations to be applied:</u>
- f(x) → f(-x) reflection over y-axis
- f(-x) → f(-2x) stretch horizontally by a factor of 2
- f(-2x) → f(-2x + 8) translate 8 units right
- f(-2x + 8) → 4f(-2x + 8) stretch vertically by a factor of 4
- 4f(-2x + 8) → 4f(-2x + 8) + 6 translate 6 units up
