$\bf \textit{Sum and Difference Identities}
\\\\
cos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta)
\\\\
cos(\alpha - \beta)= cos(\alpha)cos(\beta) + sin(\alpha)sin(\beta)\\\\
-------------------------------$

$\bf {cos(\alpha - \beta)-cos(\alpha+\beta)}=2sin(\alpha)sin(\beta)
\\\\\\
\stackrel{\textit{left-hand-side}}{[cos(\alpha)cos(\beta) + sin(\alpha)sin(\beta)]-[cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta)]}
\\\\\\
\underline{cos(\alpha)cos(\beta)} + sin(\alpha)sin(\beta)-\underline{cos(\alpha)cos(\beta)} + sin(\alpha)sin(\beta)
\\\\\\
sin(\alpha)sin(\beta)+ sin(\alpha)sin(\beta)\implies 2 sin(\alpha)sin(\beta)$

7 0

3 years ago

Find the length of the hypotenuse !!

bearhunter [10]

Answer:

Step-by-step explanation:

To find the hypotenuse, you would use the Pythagorean theorem.

$A^{2} +B^{2} =C^{2}$