The formula for E(x) would be SUM[ X(n)P(n)] from n = 1 to n = infinity until we get the prime number
In the given problem, a 10-sided die with 1-10 numbers is rolled until we get a prime number
Prime numbers between 1-10 = 2,3,5,7 (4 prime numbers)
Non - prime numbers = 1,4,6,8,9,10( 6 non-prime number)
Let X be the number of times the die is rolled
The probability of getting a prime =
![P(Prime) = \frac{4}{10}](https://tex.z-dn.net/?f=P%28Prime%29%20%3D%20%5Cfrac%7B4%7D%7B10%7D)
Now, the value of
E(X)=∑x.P(x) [ x-> {1, infinity}]
= P(1)X(1) +P(2)X(2)+P(3)X(3)+P(4)X(4)........+ P(n)X(n)
= 1.
+ 2.
.
+ 3.
.![\frac{6}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B10%7D)
+ 4.
.
.
.
.......
Hence, this is the value of E(x)
To learn more about Prime number, here
brainly.com/question/9315685
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