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scoray [572]
3 years ago
13

Solve (x-3) (x+2) = 0 and x² - 25​

Mathematics
2 answers:
Nookie1986 [14]3 years ago
7 0

Answer:

its 2 x I think u can defirantate

SSSSS [86.1K]3 years ago
4 0

x^{2} -25\\x^{2} -5^{2} \\(x-5)(x+5)

Answer:

Step-by-step explanation:

(x-3) (x+2) = 0\\(x * x )+(x*+2)- (3*x)-(3*2)=0\\x^{2} +2x-3x-6=0\\Simplify : +2x-3x ,to = -x\\x^{2} -x-6 =0\\

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Step-by-step explanation:

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2 years ago
What is 64,005,874 in word and expanded form and 30,679,100
MakcuM [25]
64005874  
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8 0
3 years ago
The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding
melamori03 [73]

Answer:

We conclude that the mean wedding cost is less than $30,000 as advertised.

Step-by-step explanation:

We are given the following data set:(in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{236100}{8} = 29512.5

Sum of squares of differences = 3408750

S.D = \sqrt{\frac{3408750}{7}} = 697.82

Population mean, μ = $30,000

Sample mean, \bar{x} = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars} We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975

Now,

t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894

Since,                  

t_{stat} < t_{critical}

We fail to accept the null hypothesis and reject it.

We conclude that the mean wedding cost is less than $30,000 as advertised.

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3 years ago
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Answer: Most planes flew below the optimal cruising speed. There is a cluster at the speeds 0.82 through 0.85. Also, the data is close to being symmetric

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2 years ago
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