Answer i need it ASAP

The median weight for a 5 foot tall male to enlist in the US Army is 114.5 lbs. This weight can vary by 17.5 lbs. Write and solv

myrzilka [38]

An absolute value inequality that represents the weight of a 5-foot male who would not meet the minimum or maximum weight requirement allowed to enlist in the Army is 97 lbs < x < 132 lbs.

<h3>What are inequalities?</h3>

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed.

It is mostly denoted by the symbol <, >, ≤, and ≥.

The median weight for a 5 foot tall male to enlist in the US Army is 114.5 lbs. This weight can vary by 17.5 lbs. Therefore, the inequality can be written as,

(114.5 - 17.5) lbs < x < (114.5 + 17.5) lbs

97 lbs < x < 132 lbs

Hence, an absolute value inequality that represents the weight of a 5-foot male who would not meet the minimum or maximum weight requirement allowed to enlist in the Army is 97 lbs < x < 132 lbs.

Learn more about Inequality:

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4 0

2 years ago

6 soccer balls for $150

eduard

the cost of one soccer ball is 150/6 or 25 dollars.

4 0

3 years ago

Read 2 more answers

What is 8/14 in lowest terms?

kumpel [21]

8/14 in lowest terms is 4/7

6 0

3 years ago

Read 2 more answers

What are the solutions of this quadratic equation?X2 - 10x= -34A.r=-8, -2B.r= 5 + 3iC.r=-5 + 3iD.r=-5 + 159

ololo11 [35]

The given equation is-

$x^2-10x=-34$

First, we move the independent term to the other side.

$x^2-10x+34=0$

Now, we have to use the quadratic equation to find the solutions.-

$x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Where, a = 1, b = -10, and c = 34.

Replacing these values in the formula, we have.

$\begin{gathered} x_{1,2}=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(1)(34)}}{2(1)} \\ x_{1,2}=\frac{10\pm\sqrt[]{100-136}}{2}=\frac{10\pm\sqrt[]{-36}}{2} \end{gathered}$

But, there's no square root of -36 because it's a negative. To solve this issue, we use complex numbers that way, we would have solutions.

$x_{1,2}=\frac{10\pm\sqrt[]{36}i}{2}=\frac{10\pm6i}{2}=5\pm3i$ <h2>Therefore, the solutions are</h2> $\begin{gathered} x_1=5+3i \\ x_2=5-3i \end{gathered}$ The right answer is B.

5 0

2 years ago

Please help will mark Brainly

SVETLANKA909090 [29]

Answer: C

Step-by-step explanation:

We are given the information that:

The airplane is at 50,000 feet
It descends 2,500 feet in 1 minute
x = minutes

For ease of solving this question, let's set the number of minutes (x) to 1.

In one minute, we know the plane will drop to 47,500 feet. (50,000 - 2,500(x))

There are multiple ways to write this equation bu shifting around negative and positive values. Another way to write this equation would be (-2,500(x) + 50,000). That would be choice C.

Try it out~

$(-2,500(x) + 50,000)\\ (-2,500(1) + 50,000)\\ (-2,500 + 50,000)\\47,500$

It works, so our answer is C.

5 0

4 years ago