To solve this, first we'll find the area of the rectangle A,
Area=length × width
?=24m×20m
480m=24m×20m
480m squared=area of the rectangle A
now we'll find the width of rectangle B,
"the width of rectangle B is 12 meters less than the width of rectangle A",
20m-12m= 8m
8m=width of rectangle B
finally we'll find the length of rectangle B,
area of the rectangle B= 480msquared
width= 8m
length=? (to find this divide the area by the width)
480÷8=60m
length of the rectangle B=60m
Answer:
The length and width of the parking lot is 78 meters and 114 meters respectively.
Step-by-step explanation:
Given;
Perimeter of the parking lot = 
Solution,
Let the width of the parking lot be x.
Then, according to question length = (x-36).
The perimeter of a rectangle is sum of all the sides of rectangle. Which is given by an expression;

Now substituting the values, we get;

Width = 
Length = 
Hence the length and width of the parking lot is 78 meters and 114 meters respectively.
The correct answer is X = -5
Answer:
y= (x+1)(x+ .5) (x+ 3.5)
y= (x+1) (X - .5) (x-3.5)
y = (x-1) (X-.5) (x-3.5)
y= (x+1) (X- .5) (x +3.5)
Step-by-step explanation:
Just multiply !!
so 1 inch = 5 miles
3.5 inch must be 3.5×5 = 17.5 miles
so the answer is 17.5 miles !!