6 3/4
to turn a mixed number to an improper fraction...
take ur whole number (6) and multiply it by ur denominator (4)....6 * 4 = 24...now add that to ur numerator (3).....24 + 3 = 27...now put that over ur original denominator (4).......27/4 <== ur improper fraction
basically, ur just doing this : (6 * 4 + 3) / 4 = (24 + 3) / 4 = 27/4
Answer:
288 * pi inches cube
Step-by-step explanation:
First we do, 6 ^ 3 = 216.
Then we do 4/3 * 216 to get 288.
So the answer is 288pi in^3
Answer:
8.70%
Step-by-step explanation:
Percentage error = (difference between estimated value and actual value / actual amount spent) x 100
difference between estimated value and actual value = estimated value - actual amount
$250 - $230 = $20
($20 / $230) x 100 = 8.6957%
Answer:
0 10
1 20
Step-by-step explanation:
0,0
1,20
2,40
3,50
4 60
Step-by-step explanation:
Let's take the RHS,
we've,
<h3>(<u>Cosa</u><u>/</u><u>2</u><u> </u><u>-</u><u> </u><u>sina</u><u>/</u><u>2</u><u>)</u></h3><h3>(<u>Cosa/</u><u>2</u><u> </u><u>+</u><u> </u><u>sina</u><u>/</u><u>2</u><u>)</u></h3>
Let's Rationalise the Denominator.
we get,
<h3>(<u>Cosa/</u><u>2</u><u> </u><u>-</u><u> </u><u>sina</u><u>/</u><u>2</u><u>)</u><u>^</u><u>2</u></h3><h3><u>(</u><u>cosa</u><u>/</u><u>2</u><u>)</u><u>^</u><u>2</u><u> </u><u>-</u><u> </u><u>(</u><u>sina</u><u>/</u><u>2</u><u>)</u><u>^</u><u>2</u></h3>
The numerator is in form of (a-b)^2 and the denominator is in form of a^2-b^2. Now,
By formula,
<h3>(<u>Cosa/</u><u>2</u><u>)</u><u>^</u><u>2</u><u> </u><u>-2cosa</u><u>/</u><u>2</u><u>.</u><u>s</u><u>i</u><u>n</u><u>a</u><u>/</u><u>2</u><u> </u><u>+</u><u> </u><u>(</u><u>sina</u><u>/</u><u>2</u><u>)</u><u>^</u><u>2</u> </h3><h3> cosa</h3>
Here I substituted Cosa in place of (Cosa/2)^2 - (sina/2)^2 because it's the formula of cosa in sub multiple angle form.
<h3>In the numerator, </h3>
(sina/2)^2 + (Cosa/2)^2 =1.........( by formula)
so we have,
<h3><u>1</u><u> </u><u>-</u><u> </u><u>2</u><u>s</u><u>i</u><u>n</u><u>a</u><u>/</u><u>2</u><u>.</u><u>c</u><u>o</u><u>s</u><u>a</u><u>/</u><u>2</u></h3><h3>Cosa</h3>
<h3 /><h3 /><h3><u>1</u><u> </u><u>-</u><u> </u><u>sina</u> {because 2sina/2.cosa/2=sina)</h3><h3>Cosa</h3>
LHS proved.
Thank You.