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m_a_m_a [10]
3 years ago
14

Help me please and thank you!​

Mathematics
1 answer:
mamaluj [8]3 years ago
8 0
7^6 is the correct answer
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Answer:

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3 years ago
A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th
Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner.  The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

\tan\theta=\frac{Perpendicular}{base}

Here, \theta=11.1^{\circ} ,Perpendicular AB = 4000

\tan\theta=\frac{AB}{BC}

\tan 11.1^{\circ} =\frac{4000}{BC}

Solving for BC, we get,

BC=\frac{4000}{\tan 11.1^{\circ} }

BC=\frac{4000}{0.196} (approx)

BC=20408.16(approx)  

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

8 0
3 years ago
Rewarding brainly for correct answer
Likurg_2 [28]
Second option. the middle 50%
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Solve by elimination <br> X - 6y + 2z = 5<br> 2x-3y+z=4<br> 3x + 4y - z = -2
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Answer:

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Step-by-step explanation:

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I think it is 52 degrease

Step-by-step explanation:

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3 years ago
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