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Dominik [7]
3 years ago
6

HELP PLEASEEE EMERGENCY

Mathematics
1 answer:
dezoksy [38]3 years ago
5 0

Answer:

y=2/3×+6

Step-by-step explanation:

y-2=2/3(×+6)

y=2/3x4+2

y=2/3×+6

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Two lines, A and B, are graphed (Look at the picture):
Snezhnost [94]

Answer:

B. (2,8), because both equations intersect at this point

3 0
3 years ago
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How do you simplify 8*1/10
Lelechka [254]

Answer:

Improper its 81/10

Step-by-step explanation:

8   1/10~ we should multiply denominator with whole number then add numerator:

10 x 8 = 80+ 1 = 81

In improper its- 81/10

Hope this helps :D

8 0
3 years ago
What is and how do you do it?<br><br> H(x) = 4x-2<br> G(x) = x^2 -5<br><br> Find h(x) + g(x)
sineoko [7]

h(x)=4x-2\\\\(x)=x^2-5\\\\h(x)+g(x)=(4x-2)+(x^2-5)=x^2+4x+(-2-5)\\\\=x^2+4x-7

6 0
3 years ago
I need help please ASAP full points
kotegsom [21]

The best way to solve this problem is with a simple equation: part = percent (in decimal form) x whole

In this problem, we're trying to solve for the <em>whole </em>amount that the camera can hold, so we'll assign that the variable w.

We can use the information they gave us - 96 is the <em>part</em>, and 24% is the percent. We'll convert that to decimal form - 0.24

Then, we just plug these values back into the above equation:

96 = 0.24w

Divide both sides by 0.24 to get w on it's own, and you have your answer!

400 = w

Therefore, the memory card can hold up to 400 pictures.


Note: this equation is <em>super </em>helpful. It's good to have on hand for any problem involving percents, because you can solve for the part, percent, or whole depending on the problem.

4 0
3 years ago
(1 point)
AlekseyPX

Answer:

  20 + 3x ≥ 50

Step-by-step explanation:

After x days, John will have added 3x points to his total. The new total will be ...

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We want that value to be at least 50, so we use the symbol "greater than or equal to" to express that relationship:

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Brainly makes available a table of math symbols so you can choose the appropriate one to use in your expression. The number 2 is not the same as the symbol ≥. Using incorrect symbols makes it very difficult to tell what the intended problem is.

8 0
3 years ago
Read 2 more answers
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