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pickupchik [31]
3 years ago
5

Solve the following question. *

Mathematics
1 answer:
n200080 [17]3 years ago
7 0

Answer:

The mean of x and y is equal to t.

Step-by-step explanation:

Given that,

The mean of t and t+2 is x.

The mean of t and t-2 is y.

i.e.

x=\dfrac{t+t+2}{2}\\\\x=(t+1)

and

y=\dfrac{t+t-2}{2}\\\\x=(t-1)

The mean of x and y is :

M=\dfrac{x+y}{2}\\\\M=\dfrac{(t+1)+(t-1)}{2}\\\\M=\dfrac{2t}{2}\\\\M=t

Hence, the mean of x and y is equal to t.

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What is -4 3/4+2 1/2
OLga [1]
The answer as a mixed number: -2 1/4
the answer as a decimal: -2.25
the answer as an improper fraction: -9/4
3 0
3 years ago
16+ n/4 =22 <br><br> Help me solve please and thank you :))
Luden [163]

Answer:

n = 24

Step-by-step explanation:

16+ n/4 =22

Subtract 16 from each side

16-16+ n/4 =22-16

n/4 = 6

Multiply each side by 4

n/4*4 = 6*4

n = 24

4 0
3 years ago
D) Round 0.00208815 to 3 significant figures.
Lostsunrise [7]

Answer:

= 0.00209

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Below is the graph of y= x.<br> Translate it to make it the graph of y=<br> x-1 + 4.
Oduvanchick [21]
  • First, to shift the graph of y=x 1 unit to the right, so y=x-1
  • Second, to shift the graph of y=x-1 4 units to the left, so y=x-1+4

<h2>Explanation:</h2>

To translate the graph of a function is part of Rigid Transformations because the basic shape of the graph is unchanged

Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:

\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c

\bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)

In this case, we have the graph of:

y=x

And we need to translate it to make it the graph of:

y=x-1+4

According to our rules we need:

  • First, to shift the graph of y=x 1 unit to the right, so y=x-1
  • Second, to shift the graph of y=x-1 4 units to the left, so y=x-1+4

But y=x-1+4 is the same as y=x+3, so the previous steps can be simplified as:

  • Shifting the graph of y=x 3 unit to the left.

Below are shown those graphs:

  • The blue one is y=x
  • The red one is y=x-1+4

<h2>Learn more:</h2>

Shifting graphs: brainly.com/question/10010217

#LearnWithBrainly

6 0
3 years ago
Consider the following statement: The square of a prime number is not prime. (a) Write this as an if-then statement, using caref
Hitman42 [59]

The square of a prime number is not prime.

a) let x ∈ R, If x  ∈ {prime numbers}, then x^{2}∉{prime numbers}

there says that if x is a real and x is in the set of the prime numbers, then the square of x isn't in the set of prime numbers.

b) Prove or disprove the statement.

ok, if x is a prime number, then x only can be divided by himself. Now is easy to see that x^{2} = x*x can be divided by himself and x, then x*x is not a prime number, because can be divided by another number different than himself

7 0
3 years ago
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