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3 years ago

Solve the following question. *

Mathematics

1 answer:

n200080 [17]3 years ago

7 0

Answer:

The mean of x and y is equal to t.

Step-by-step explanation:

Given that,

The mean of t and t+2 is x.

The mean of t and t-2 is y.

i.e.

$x=\dfrac{t+t+2}{2}\\\\x=(t+1)$

and

$y=\dfrac{t+t-2}{2}\\\\x=(t-1)$

The mean of x and y is :

$M=\dfrac{x+y}{2}\\\\M=\dfrac{(t+1)+(t-1)}{2}\\\\M=\dfrac{2t}{2}\\\\M=t$

Hence, the mean of x and y is equal to t.

You might be interested in

What is the simplest form of the expression sqrt3-sqrt6 ------------------ sqrt3+sqrt6

Solnce55 [7]

Multiply numerator and denominator by
$\frac{ \sqrt{3} -\sqrt{6} }{ \sqrt{3} = \sqrt{6} } 
$

Things should simplify pretty nicely.

6 0

4 years ago

Which of the following are perpendicular to the line y=-1/3x+5 (three answers)

Mkey [24]

Y = -1/3x + 5....slope here is -1/3. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So ur perpendicular line will have a slope of 3.

y = 3x....has a slope of 3, so this is perpendicular.
3x - y = 2.....y = 3x- 2.....has a slope of 3 and is therefore perpendicular
3x - y = 6.....y = 3x - 6...has a slope of 3 and is perpendicular

6 0

3 years ago

Find the sum of 14 + 8 + 2+ ... + ( 274) + (-280).

Musya8 [376]

The sum of the given sequence is -6384.

Step-by-step explanation:

The given Arithmetic sequence is 14 + 8 + 2+ ... + ( 274) + (-280).

The first term of the sequence = 14
The last term of the sequence = -280
The common difference ⇒ 14 - 8 = 6

To find the number of terms in the sequence :

The formula used is $n = (\frac{a_{n}-a_{1}} {d})+1$

where,

n is the number of terms.
$a_{n}$ is the late term which is -280.
$a_{1}$ is the first term which is 14.
d is the common difference which is 6.

Therefore, $n =(\frac{-280-14}{6}) +1$

⇒ $n =( \frac{-294}{6}) + 1$

⇒ $n = -49 + 1$

⇒ $n = -48$

⇒ n = 48, since n cannot be negative.

∴ The number of terms, n = 48.

To find the sum of the arithmetic progression :

The formula used is $S = \frac{n}{2}(a_{1} + a_{n} )$

where,

S is the sum of the sequence.
$a_{1}$ is the first term which is 14.
$a_{n}$ is the late term which is -280.

Therefore, $S = \frac{48}{2}(14+ (-280))$

⇒ $S = \frac{48}{2}(-266)$

⇒ $S = 48 \times -133$

⇒ $S = -6384$

∴ The sum of the given sequence is -6384.

3 0

3 years ago

Which system of equations is graphed below?

algol [13]

(Pls give brainliest! :D)

Answer:

B

Step-by-step explanation:

You know that the graph intercepts at the point of (4,-2)

Where x = 4 and y = -2.

This means that whenever you plug a value of x in the equation it should give the value of y.

For example when you plug x= 4 into the equation (B), it should look like this.

4- y = 6, solving for y gives us the value negative 2.

This means that it does give us this point, however, as the graph shows us, both lines meet at the point which means that both equation should give us this point.

If we substitute x = 4 in the second equation of b, we should be able to get 3(4) + 4y = 4. Solving for y gives us -2.

Hope this helps!

-Yumi

4 0

3 years ago

Read 2 more answers

Given the expressions are equivalent (3x + 2)^2 - (mx^2 + 7) = 5x^2 + 12x - 3 2 - 3 What is the value of m?

BartSMP [9]

Answer:M=4

Step by step answer

9x^2-mx^2+12x-3=5x^2+12x-35

9x^2-mx^2+12x-3+3=5x^2+12x-35+3

9x^2-mx^2+12x=5x^2+12x-32

9x^2-mx^2+12x-12x=5x^2+12x-32-12x

9x^2-mx^2-5x^2=5x^2-32-5x^2

-mx^2+4x^2=-32

x^2(-m+4)=-32

M=4

Hope this helps (;

7 0

3 years ago