Answer:
no
Step-by-step explanation:
4x -3 = 16
x=19/4
4(x-3) = 16: Distribute the number in the parenthesis with 4 and you get:
4x-12=16
x=7
4x-12=16 is not the same as 4x-3=16
Therefore they do not have the same solution.
Answer:
x = 50
Step-by-step explanation:
Since MNP is a tangent to the circle at N, then
∠ ONP = 90° , so
∠ ONL = 90° - 55° = 35°
OL = ON ( both radii of the circle )
Thus Δ ONL is isosceles and the base angles are congruent
∠ OLN = ∠ ONL = 35°
JKLN is a cyclic quadrilateral whose opposite angles are supplementary, that is
∠KJN + ∠ KLN = 180 , substitute values
95 + 35 + x = 180
130 + x = 180 ( subtract 130 from both sides )
x = 50
In pure translation or in roll without slip?
In pure translation, just use Fnet = m*a. Fnet = 7.5 Newtons
In roll without slip it has effectively more inertia than 5 kilograms. The effective inertia can be found as:
m_effective = m + I/r^2
For a uniform solid sphere, I = 2/5*m*r^2
So m_effective = 7/5*m
To make a 5 kg bowling ball accelerate at 1.5 m/s^2 in roll without slip, it requires Fnet = 10.5 Newtons, and this ASSUMES that all forces causing the net force on it have lines of action through its center of mass (most common case).
i hope this is what ur looking for
A Quadrilateral A B C D in which Sides AB and DC are congruent and parallel.
The student has written the following explanation
Side AB is parallel to side DC so the alternate interior angles, angle ABD and angle BDC, are congruent. Side AB is equal to side DC and DB is the side common to triangles ABD and BCD. Therefore, the triangles ABD and CDB are congruent by SAS.
The student has also written
angles DBC and ADB are congruent and sides AD and BC are congruent. Angle DBC and angle ADB form a pair of alternate interior angles. Therefore, AD is congruent and parallel to BC. Quadrilateral ABCD is a parallelogram because its opposite sides are equal and parallel.
Postulate SAS completely describes the student's proof.
Because if in a quadrilateral one pair of opposite sides are equal and parallel then it is a parallelogram.
