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Vinil7 [7]
3 years ago
9

Musical notes are classified by frequency. The note middle C has a frequency of 262 hertz. The note C above middle C has a frequ

ency of 524 hertz. The note C below middle C has a frequency of 131 hertz.
1) Write an equation of the sine function that represents middle C if its amplitude is 0.2.

2)Write an equation of the sine function that represents C above middle C if its amplitude is one half that of middle C.

3)Write an equation of the sine function that represents C below middle C if its amplitude is twice that of middle C.
Mathematics
1 answer:
Ugo [173]3 years ago
7 0

9514 1404 393

Answer:

  1)  f(t) = 0.2·sin(524π·t)

  2)  f(t) = 0.1·sin(1048π·t)

  3)  f(t) = 0.4·sin(262π·t)

Step-by-step explanation:

The general form of the desired equation is ...

  f(t) = A·sin(2πf·t)

__

1) f = 262; A = 0.2

  f(t) = 0.2·sin(524π·t)

__

2) f = 524; A = 0.1

  f(t) = 0.1·sin(1048π·t)

__

3) f = 131; A = 0.4

  f(t) = 0.4·sin(262π·t)

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4x−3=16=4(x−3)=16 <br> Do they have the same solution?
AnnZ [28]

Answer:

no

Step-by-step explanation:

4x -3 = 16

x=19/4

4(x-3) = 16: Distribute the number in the parenthesis with 4 and you get:

4x-12=16

x=7

4x-12=16 is not the same as 4x-3=16

Therefore they do not have the same solution.

5 0
3 years ago
Read 2 more answers
6. Give the slope of each line. Also, state if the lines are parallel (yes or no). Hint: rewrite to slope-intercept form. AB: 2y
Dmitriy789 [7]

Answer:

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8 0
3 years ago
Can someone please help me ASAP​
konstantin123 [22]

Answer:

x = 50

Step-by-step explanation:

Since MNP is a tangent to the circle at N, then

∠ ONP = 90° , so

∠ ONL = 90° - 55° = 35°

OL = ON ( both radii of the circle )

Thus Δ ONL is isosceles and the base angles are congruent

∠ OLN = ∠ ONL = 35°

JKLN is a cyclic quadrilateral whose opposite angles are supplementary, that is

∠KJN + ∠ KLN = 180 , substitute values

95 + 35 + x = 180

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4 0
3 years ago
What net force will make a 5 kg bowling ball accelerate by 1.5 m/s square 2?
s2008m [1.1K]

In pure translation or in roll without slip?

In pure translation, just use Fnet = m*a.  Fnet = 7.5 Newtons

In roll without slip it has effectively more inertia than 5 kilograms.  The effective inertia can be found as:

m_effective = m + I/r^2

For a uniform solid sphere, I = 2/5*m*r^2

So m_effective = 7/5*m

To make a 5 kg bowling ball accelerate at 1.5 m/s^2 in roll without slip, it requires Fnet = 10.5 Newtons, and this ASSUMES that all forces causing the net force on it have lines of action through its center of mass (most common case).

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3 0
3 years ago
The figure below shows a quadrilateral ABCD. Sides AB and DC are congruent and parallel: A quadrilateral ABCD is shown with the
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A Quadrilateral A B C D in which Sides AB and DC are congruent and parallel.

The student has written the following explanation

Side AB is parallel to side DC so the alternate interior angles, angle ABD and angle BDC, are congruent. Side AB is equal to side DC and DB is the side common to triangles ABD and BCD. Therefore, the triangles ABD and CDB are congruent by SAS.

The student has also written

angles DBC and ADB are congruent and sides AD and BC are congruent. Angle DBC and angle ADB form a pair of alternate interior angles. Therefore, AD is congruent and parallel to BC. Quadrilateral ABCD is a parallelogram because its opposite sides are equal and parallel.

Postulate SAS completely describes the student's proof.

Because if in a quadrilateral one pair of opposite sides are equal and parallel then it is a parallelogram.

 

6 0
3 years ago
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