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Savatey [412]
3 years ago
9

To determine the number of trout in a​ lake, a conservationist catches 132 ​trout, tags them, and throws them back into the lake

.​ Later, 22 trout are​ caught; 11 of them are tagged. How many trout would the conservationist expect to be in the​ lake?
The conservationist would expect that there are how many trout in the lake?
Mathematics
1 answer:
Drupady [299]3 years ago
4 0
I wish I knew I’m havin trouble
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The revenue equation (in hundreds of millions of dollars) for barley production in a certain country is approximated by R(x) = 0
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Answer:

The marginal-revenue equation is R'(x)=0.1226x+1.1584.

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The derivative R'(x) of the revenue function is called the marginal revenue function and is the rate of change of revenue with respect to the number of units sold.

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R'(x)=\frac{d}{dx}R(x) = \frac{d}{dx}(0.0613x^{2} +1.1584x+2.4813)\\\\=\frac{d}{dx}\left(0.0613x^2\right)+\frac{d}{dx}\left(1.1584x\right)+\frac{d}{dx}\left(2.4813\right)\\\\R'(x)=0.1226x+1.1584

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200,000,000 bushels we use x = 2, since x is in units of hundreds of million of dollars.

R'(x)=0.1226\cdot \:2+1.1584\\\\R'(x)=0.2452+1.1584\\\\R'(x)=1.4036

650,000,000 bushels we use x = 65, since x is in units of hundreds of million of dollars.

R'(x)=0.1226\cdot \:65+1.1584\\\\R'(x)=7.969+1.1584\\\\R'(x)=9.1274

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