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Gelneren [198K]
3 years ago
9

I know the answer but I need an explanation of how it is the answer plss.

Mathematics
2 answers:
Mashcka [7]3 years ago
4 0

Answer: I got the answer by adding and subtracting

Step-by-step explanation:

dusya [7]3 years ago
4 0
I can help you with the first correct answer first.

The dots represent how many people are at a certain height. Basically 3 people are 78 in.
The choice says that more than half of the players are 79 in or taller. So start at 79 (between 78 and 80).
We see that two players are at 79 in. Now check 80 all the way to 84 (what on earth am I saying-)
Add the dots, starting from 79 all the way to 84. 8 players are 79 in or taller.

Now what about the ones lower than 79? Count those too, starting from 78 to 69. Once you do that, you will see that 7 people are less that 79 in. Which means that more than half of the players are 79 in or taller. That’s how you do it.

For the third one, the tallest player is 84 in. The shortest is 69 in. 84 - 69 = 15. So that’s how the last option is right :)
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IrinaK [193]
16,000,000/2.25 =
7,111,111.11 milligrams of ozone PER DAY
How much per week?
7,111,111.11 * 7 =
49,777,777.78
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49,777,778 milligrams of ozone per week
3 0
3 years ago
There is three fourths of a box of cereal remaining. You eat 2/5 of the remaining cereal. What fraction of the box do you eat
likoan [24]
You would eat 3/10 of the box because 3/4 times 2/5 is 3/10. Whenever you see the word "of" it means multiplication.
3 0
3 years ago
At PRMS, 25% of the 124 students Mrs. Pasternak teaches buy their lunches in the cafeteria. How many students buy their lunches
Ksju [112]
25% = 0.25
124 x 0.25 = 31

31 students bought their lunch.

Part = 31
Percent = 25%
Whole = 124

Hope this helps! ✨
6 0
3 years ago
Consider the region bounded by the curves y=|x^2+x-12|,x=-5,and x=5 and the x-axis
Tasya [4]
Ooh, fun

what I would do is to make it a piecewise function where the absolute value becomse 0

because if you graphed y=x^2+x-12, some part of the garph would be under the line
with y=|x^2+x-12|, that part under the line is flipped up

so we need to find that flipping point which is at y=0
solve x^2+x-12=0
(x-3)(x+4)=0
at x=-4 and x=3 are the flipping points

we have 2 functions, the regular and flipped one
the regular, we will call f(x), it is f(x)=x^2+x-12
the flipped one, we call g(x), it is g(x)=-(x^2+x-12) or -x^2-x+12
so we do the integeral of f(x) from x=5 to x=-4, plus the integral of g(x) from x=-4 to x=3, plus the integral of f(x) from x=3 to x=5


A.
\int\limits^{-5}_{-4} {x^2+x-12} \, dx + \int\limits^{-4}_3 {-x^2-x+12} \, dx + \int\limits^3_5 {x^2+x-12} \, dx

B.
sepearte the integrals
\int\limits^{-5}_{-4} {x^2+x-12} \, dx = [\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-5}_{-4}=(\frac{-125}{3}+\frac{25}{2}+60)-(\frac{64}{3}+8+48)=\frac{23}{6}

next one
\int\limits^{-4}_3 {-x^2-x+12} \, dx=-1[\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-4}_{3}=-1((-64/3)+8+48)-(9+(9/2)-36))=\frac{343}{6}

the last one you can do yourself, it is \frac{50}{3}
the sum is \frac{23}{6}+\frac{343}{6}+\frac{50}{3}=\frac{233}{3}


so the area under the curve is \frac{233}{3}
6 0
3 years ago
Watch help video<br> In AUVW, the measure of represents the cosine of
DedPeter [7]

Answer:

80/89

Step-by-step explanation:

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8 0
3 years ago
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