Graph the line y+5=1/4(x-3)

Jane has her height measured using a metric ruler as 1.6 meters. She would like to know her height in inches. She knows that the

slavikrds [6]

Answer:

Jane's height is 63 inches.

Step-by-step explanation:

Given:

Jane has her height measured using a metric ruler as 1.6 meters. She would like to know her height in inches. She knows that there are 100 centimeters in a meter and 2.54 centimeters in an inch.

Now, to find jane's height to the nearest inch.

The height of Jane measured using metric ruler = 1.6 meters.

As, 1 meter = 100 centimeters.

So, by using conversion factor we convert the height of Jane into centimeters from meters:

$1.6\ meter=1.6\times 100$

$=160\ centimeters.$

Height of Jane in centimeters = 160.

As given, 2.54 centimeters in an inch.

Now, we convert the centimeters by using unitary method:

If, 2.54 centimeters = 1 inch.

Then, 1 centimeters = $\frac{1}{2.54} \ inch$

So, 160 centimeters = $\frac{1}{2.54}\times 160$

$=\frac{160}{2.54}$

$=62.99\ inches.$

Thus, the height nearest to inch = 63 inches.

Therefore, Jane's height is 63 inches.

4 0

3 years ago

HELP ASAP with this question

mihalych1998 [28]

A, the student failed to distribute. In his step one, he got 3x + 2 =y, but it's actually 3x + 6 = y

I got this by distributing 3 to both x and 2, which is 3x and 6.

8 0

3 years ago

Answer this question. please

dimaraw [331]

Answer:

$\boxed{\textsf{ The total surface area of the cuboid is \textbf{62 cm} $\sf ^2$ .}}$

Step-by-step explanation:

Given that the base area of the cuboid is 7cm² . And it's volume is 21cm³ . We need to find its total surface area . Now here we need to find the height . We can find height as ,

Height :-

$\qquad\boxed{\boxed{\sf Height =\dfrac{ Volume}{Area } }}$

$\sf\implies Height =\dfrac{Volume}{Area} \\\\\sf\implies h =\dfrac{ 21cm^3}{7cm^2}\\\\\implies \boxed{ \pink{\frak { Height = 3 cm.}}}$

$\rule{200}2$

Let's find out the Total surface area .

TSA of cuboid :-

$\qquad\boxed{\boxed{\sf TSA_{(cuboid)} =2(lb + bh + hl ) }}$

Put on the respective values :-

$\sf\implies TSA_{(cuboid)}= 2( lb + bh + hl )\\\\\sf\implies TSA_{(cuboid)}= 2( 7cm\times 1cm + 1cm\times 3cm + 3cm \times 7 cm ) \\\\\sf\implies TSA_{(cuboid)}=2 ( 7cm ^2+3cm^2+21cm^2 ) \\\\\sf\implies TSA_{(cuboid)}= 2\times 31cm^2 \\\\\sf\implies \boxed{\pink{\frak{ TSA_{(cuboid)}= 62 cm^2}}}$

3 0

3 years ago

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Divide x4 + 7 by x - 3.. A] x³ - 3x² - 9x - 27 R 88. B] x³ + 3x² + 9x - 27 R -74. C] x³ + 3x² + 9x + 27 R 88

Nastasia [14]

divide a polynomial p(x) by (x-3). Add and subtract the multiple of (x-3) that has the same highest-power term as p(x), then simplify to get a smaller-degree polynomial r(x) plus multiple of (x-3). 

The multiple of (x-3) that has x^4 as its leading term is x^3(x-3) = x^4 - 3x^3. So write: 

x^4 + 7 = x^4 + 7 + x^3(x - 3) - x^3(x - 3) 
= x^4 + 7 + x^3(x - 3) - x^4 + 3x^3 
= x^3(x - 3) + 3x^3 + 7 

That makes r(x) = 3x^3 + 7. Do the same thing to reduce r(x) by adding/subtracting 3x^2(x - 3) = 3x^3 - 9x^2: 

= x^3(x - 3) + 3x^3 + 7 + 3x^2(x - 3) - (3x^3 - 9x^2) 
= x^3(x - 3) + 3x^2(x - 3) + 9x^2 + 7 

Again to reduce 9x^2 + 7: 
= x^3(x - 3) + 3x^2(x - 3) + 9x^2 + 7 + 9x(x - 3) - (9x^2 - 27x) 
= x^3(x - 3) + 3x^2(x - 3) + 9x(x - 3) + 27x + 7 

And finally write 27x + 7 as 27(x - 3) + 88; 
x^4 + 7 = x^3(x - 3) + 3x^2(x - 3) + 9x(x - 3) + 27(x - 3) + 88 

Factor out (x - 3) in all but the +88 term: 
x^4 + 7 = (x - 3)(x^3 + 3x^2 + 9x + 27) + 88 

That means that: 
(x^4 + 7) / (x - 3) = x^3 + 3x^2 + 9x + 27 with a remainder of 88

3 0

3 years ago

Read 2 more answers

Solving by substitution

Lesechka [4]

* يدرج صوت سيارة الإسعاف*

6 0

3 years ago

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