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attashe74 [19]
3 years ago
12

Sausages come in packets of 7. Bread rolls come in packets of 5. Dan wants to buy enough packs of sausages and rolls so that the

re are an equal number of sausages and rolls. What is the minimum number of sausages and rolls he needs to buy?
Mathematics
2 answers:
Olenka [21]3 years ago
7 0

Answer:

7 packs of rolls

5 packs of sausages

Step-by-step explanation:

The easiest way to solve this question is to make a table with 3 columns

Rolls          5   10   15 20 25 30 35

Sausages  7    14   21 28 35 42 49

# packs    1    2    3    4   5    6  7

Looking at the table you can see that the first number that matches up is 35 so looking at that point we would need 7 packs of rolls and 5 packs of sausages.

den301095 [7]3 years ago
3 0

Answer:

5 packs of sausages7 packs of rolls

Step-by-step explanation:

You need to find the common multiple.

5 x 7 = 35.

We know that before this there is no other common multiple becuase 7 does not multiply to a number that ends with a 0 or 5 until 35.

So, he will need to buy:

- 5 packs of sausages

- 7 packs of rolls

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Abby filled her goodie bags with 4 cookies and 3 candy bars and spent a total of $10.25 per bag. Marissa filled her goodie bags
Paladinen [302]
Let's start by writing a system of linear equations:
c -> cookies 
cb -> candy bars
(You can use any abbreviations to your preference)

Abby:
4 cookies 
3 candy bars
$10.25 per bag
The equation would be:
4c+ 3cb = $10.25

Marissa:
2 cookies
7 candy bars
$14.75 per bag
The equation would be:
2c + 7cb = $14.75

So our linear equation system would be:
<span>4c+ 3cb = $10.25
</span><span>2c + 7cb = $14.75

I would try to get rid of one variable so I can solve for the other variable. In this case, it is easier to get rid of c since I can multiply the second equations by 2. Then it would subtract the two equations.

(2c + 7cb = $14.75) 2 = 4c + 14 cb = $29.50

      4c + 3cb = $10.25
   -  4c+14 cb = $29.50                    (4c would get canceled.)
---------------------------------
             -11 cb = - $19.25                (Divide by -11 to solve for cb)
</span>             ---------   -------------
              -11           -11
            
             cb = $1.75

Now we know cb (candy bar) cost, we would substitute this value into cb into one of the equations. It doesn't matter which equation you put it in. I will substitute it in the first equations. 

  4c + 3 (1.75) = $10.25
  4c + 5.25 = $10.25                       (Multiply 3 by 1.75)
       -5.25       -5.25                         (Subtract 5.25 on both sides)
             4c = 5                                 (Divide by 4 on both sides to get c)
             ----   ---
              4      4
         
         c= 1.25

Check the work:
4(1.25) + 3(1.75) 
  = $10.25

2(1.25) + 7(1.75)
   = $14.75

Total cost:
cookies = $1.25
candy bars = $ 1.75

Hope this helps! :)

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