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den301095 [7]
3 years ago
7

Please help questions 6 , 7 and 8 50 points

Mathematics
2 answers:
Aliun [14]3 years ago
7 0

Answer:

70270

19.1

43070

Step-by-step explanation:

Six

It takes a bit to see what's going on. The liabilities are not added up correctly. If you add the 4 entries that are there you get 6270 as a total.

If his net worth is 64000 then the assets needed to overcome the liabilities is <em><u>64000 + 6270 = 70270 which is the last choice.</u></em>

Seven

Mortgage Payment % = (Amount of Mortgage/Total) *100

Mortgage Payment % = (1200 / 6270) * 100

<em><u>Mortgage Payment % = 19.1%</u></em>

Eight

From Question seven we found out that his total assets are 70270.

The assets listed under assets total

9000

5200

<u>13000</u>

27200

So the CD = Total Assets - Listed Assets

CD = 70270 - 27200

<em><u>CD = 43070</u></em>

lorasvet [3.4K]3 years ago
7 0

Answer:

im not really sureee

Step-by-step explanation:

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An airplane is flying at 180mph. A jet flying at 330 mph leaves 1 hour later traveling in the same direction. How long will it t
zimovet [89]

To solve this problem, let us first assign some variables. Let us say that:

v1 = velocity of airplane = 180 mph

t1 = time travelled by airplane

v2 = velocity of jet = 330 mph

t2 = time travelled by jet

 

Since we know that distance is the product of velocity and time, and that the distance travelled by the two must be equal for the jet to catch up to the plane, hence:

v1 * t1 = v2 * t2

But we know that:

t1 = t2 + 1

Therefore:

180 (t2 + 1) = 330 t2

180 t2 + 180 = 330 t2

150 t2 = 180

t2 = 1.2 hours

 

<span>Therefore the jet can catch up to the plane after 1.2 hours it takes off.</span>

4 0
3 years ago
Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s
stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.  

Then we have n_{1} = 25, \bar{x}_{1} = 2.04, \sigma_{1} = 0.010 and n_{2} = 20, \bar{x}_{2} = 2.07, \sigma_{2} = 0.015. The pooled estimate is given by  

\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552

a. We want to test H_{0}: \mu_{1}-\mu_{2} = 0 vs H_{1}: \mu_{1}-\mu_{2} \neq 0 (two-tailed alternative).  

The test statistic is T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}} and the observed value is t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257. T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value t_{0} falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by 2P(T0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}, i.e.,

-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}

where t_{0.025} is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

-0.03\pm(2.0167)(0.012459)(0.3), i.e.,

(-0.0225, -0.0375)

8 0
3 years ago
If f(x)= 10 sin(x) – 3 then f (30%) = ?
marissa [1.9K]

Answer:

The value of f(30) is equal to 2.

Step-by-step explanation:

The given expression is :

f(x)= 10 \sin(x) - 3

We need to find the value of f(30)

Put x = 30 in above expression.

So,

f(x)= 10 \sin(30) - 3\\\\=10\times \dfrac{1}{2}-3\\\\=5-3\\\\=2

Hence, the value of f(30) is equal to 2.

5 0
3 years ago
Negative numbers have positive square roots.<br> O A. True<br> B. False
musickatia [10]

Answer:

false

Step-by-step explanation:

7 0
3 years ago
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The fuel tank of a certain airplane can hold up to 400 gallons of fuel. Let W be the total weight of the airplane (in pounds). L
Lady bird [3.3K]
A reasonable function is W = 7F + 5000


Where W is the weight of the plane and F is the number of gallons of fuel.


The domain is the set of possible values for F. That is from 0 (empty tank) to 400 (full tank).


So the domain is F = [0,400], or what is equivalente 0 ≤ F ≤ 400.


The range is the set of values of W.


The minimum value of W is when F = 0 => W = 7(0) + 5000 = 5,000.


The maximum value of W is when F = 400 => W = 7(400) + 5000 = 7,800 


So the range is W = [5,000 ; 7,800], pr 5000 ≤ W ≤ 7,800. 
7 0
3 years ago
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