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2 years ago

6

The Hawks are starting a babysitting business. They charge an initial deposit of $25 and a rate of $4 an hour. A linear model is

written where x is the number of hours and y is the total cost of the service.

1 answer:

Sauron [17]2 years ago

7 0

What’s the question so I can answer it.

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Hypotenuse Math. 15 Points.

Rina8888 [55]

Using the Pythagorean theorem:

a^2 + b^2 = c^2

A and B are the sides and c is the hypotenuse.

4^2 + 5^2 = c^2

Simplify:

16+25 = c^2

41 = c^2

Take the square root of both sides:

c=√41

4 0

3 years ago

Read 2 more answers

Tanya is training a turtle for a race. For every 1/2 of an hour that the turtle is crawling, he can travel 3/20 of a mile. At wh

vazorg [7]

Answer:

$\frac{6}{20} \ mile\ per\ hour$

Step-by-step explanation:

Given:

For every 1/2 of an hour that the turtle is crawling, he can travel 3/20 of a mile

Question asked:

At what unit rate is the turtle crawling?

Solution:

As here<u> time taken is given</u> and the <u>distance traveled is also given </u>and hence we will apply speed and distance formula to find rate of crawling of turtle.

Time taken by turtle = $\frac{1}{2} \ hour$

Distance which can be traveled by turtle = $\frac{3}{20} \ miles$

$Speed =\frac{Distance}{Time}$

$=\frac{3}{20} \div\frac{1}{2} \\\\ =\frac{3}{20} \times\frac{2}{1} \\ \\ =\frac{6}{20}$

Therefore, the rate at which the turtle is crawling is $\frac{6}{20} \ mile\ per\ hour$

4 0

2 years ago

5 less the quotient of 14 times a number x and 9

AURORKA [14]

Answer:

$\frac{14x}{9}-5$

Step-by-step explanation:

14 times a number x : 14* x = 14x

Quotient of 14 times a number x an 9 : $\frac{14x}{9}$

5 less the quotient of 14 times a number x and 9 :

$\frac{14x}{9}-5$

7 0

2 years ago

Help please what is the answer?

Dmitrij [34]

(pemdas), parenthesis then exponents.
7 * 2 = 14
14^ 7 = 105413504

8 0

2 years ago

Help on questions 11 and 15 Add and simplify if possible

Svetllana [295]

$\frac{16+x}{x^3}+\frac{7-4x}{x^3}=\frac{16+x+7-4x}{x^3}=\frac{23-3x}{x^3}\\\\======================================\\\\\frac{5}{t-1}+\frac{3}{t}=\frac{5t}{t(t-1)}+\frac{3(t-1)}{t(t-1)}=\frac{5t+3t-3}{t^2-t}=\frac{8t-3}{t^2-t}$

7 0

2 years ago

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