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NNADVOKAT [17]
3 years ago
7

PLS HELP , ALGEBRA 2!! I WILL MARK BRAINLIEST

Mathematics
1 answer:
Oliga [24]3 years ago
8 0

Answer:

1). no

2). no

Part 2

A) (3,-2)

B) (1,0),(-3,4)

C) (4,0)

D) (3,2)

Step-by-step explanation:

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Grace is comparing cell phone plans. A prepaid phone plan costs $0.20 per minute and has no monthly fee. A contracted phone plan
Sophie [7]

Answer:

B

Step-by-step explanation:

The contracted phone plan will have the same steepness and a higher y-intercept.

4 0
3 years ago
A) If a:b = 2:5 and b:c = 3:4, find (i) a:c(ii) a:b:c
kobusy [5.1K]

Answer:

A i. a:c=3:10

ii. a:b:c=2:5:10

B i. x:z=2:5

ii. x:y:z=2:4:5

Step-by-step explanation:

A.) If a:b = 2:5 and b:c = 3:4, find (i) a:c(ii) a:b:c

a:b=a/b=2/5

b:c=b/c=3/4

a/b*b/c=a/c

2/5*3/4=a/c

6/20=a/c

3/10=a/c

Therefore, a:c=3:10

a:b:c

a:b=2:5

b:c=3:4

b is common to both ratios

The value of b in the first ratio is 5 and b is 3 in the second ratio

Lets take the LCM of both values

LCM of 5 and 3=15

So, we will change the value of b in the first ratio and second ratio to 15

By doing this, we will multiply the whole first ratio by 3

We have, 6:15

We multiply the whole second ratio by 5

We have, 15:20

Therefore a:b:c=6:15:20

=2:5:10

B. If x:y = 1:2 and y:z = 4:5,

x:y=x/y=1:2

y:z=y/z=4:5

x/y*y/z=x/z

1/2*4/5=x/z

4/10=x/z

2/5=x/z

Therefore, x:z=2:5

x:y:z

x:y=1:2

y:z=4:5

y is common to both ratio

Take the LCM of y values in both ratio

LCM of 2 and 4 =4

So,we will change the value of y in the first and second ratio to 4

By doing this, we will multiply the whole first ratio by 2

We have, 2:4

We will also multiply the whole second ratio by 1

We have, 4:5

Therefore, x:y:z=2:4:5

8 0
3 years ago
How do I solve for p and q?
Igoryamba
So this is an in-out chart.  so just follow the function.
6 0
3 years ago
H(x)=x2+2x g(x)=-2x+4 Find(h-g)(x)<br> O x2+3x+1<br> O x2+4x-4<br> O x2-4x-4<br> O -x2-4x+4
maria [59]

Answer:

Step-by-step explanation:

x^2 + 2x + 2x - 4

x^2 + 4x - 4

Option 2 is the answer

8 0
4 years ago
two joggers run 8 miles north and then 5 miles west. what is the shortest distance they must travel to return to their starting
Simora [160]

Answer:

9.43 miles and for the diagram just draw a labelled right triangle with the base running towards the left. Hope this helps!

Step-by-step explanation:

I believe you would use the pythagorean theorem which is a^2+b^2=c^2

So if

8^2+5^2=c^2

64+25=89

\sqrt{89} = 9.43

5 0
3 years ago
Read 2 more answers
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