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OlgaM077 [116]
3 years ago
11

You can solve the equation by using _____ operations to get the variable terms on one side of the equal sign and the constant te

rms on the ______ side. Then ______ both sides by the coefficient of the resulting variable term
HELPPPP PLZZZZ
Mathematics
2 answers:
Bumek [7]3 years ago
7 0

Answer:212

Step-by-step explanation:

efmkn44uf4ufh4ufh4ufh4uf4hfu4hfuhfurhfurhfu

evablogger [386]3 years ago
6 0
1st blank- order of operations
2nd blank - right
3rd blank - cross
Please mark me brainiest! :)
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The values in the table represent an exponential function. What is the common ratio of the associated geometric sequence? x: 1,
Alex73 [517]

Answer:

the answer might be b. because if you multiply it by 4 it is 512.

Step-by-step explanation:

8 0
3 years ago
Match the circle equations in general form with their corresponding equations in standard form. Not all will be used. 
Xelga [282]
<span>The standard form of the equation of a circumference is given by the following expression:

</span>(x-h)^{2}+(y-k)^{2}=r^{2} \\ \\ where \ (h, k) \ is \ the \ center \ of \ the \ circumference \ and \ r \ the \ radius
<span>
On the other hand, the general form is given as follows:

</span>x^{2}+y^{2}+Dx+Ey+F=0 \\ \\ where: \\ D=-2h, \ E=-2k, \ F=h^{2}+k^{2}-r^{2}<span>

In this way, we can order the mentioned equations as follows:

Equations in Standard Form:

</span>\bold{a)} \ (x-6)^{2}+(y-4)^{2}=56 \\ \bold{b)} \ (x-2)^{2} + (y+6)^{2}=60 \\ \bold{c)} \ (x+2)^{2}+(y+3)^{2}=18 \\ \bold{d)} \ (x+1)^{2}+(y-6)^{2}=46

Equations in General Form:

\bold{1)} \ x^{2}+y^{2}-4x+12y-20=0 \\ \bold{2)} \ x^{2}+y^{2}+6x-8y-10=0 \\ \bold{3)} \ 3x^{2}+3y^{2}+12x+18y-15=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 3, \ the \ equation \ becomes: \\ x^{2}+y^{2}+4x+6y-5=0 \\ \\ \bold{4)} \ 5x^{2}+5y^{2}-10x+20y-30=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 5, \ the \ equation \ becomes: \\ x^{2}+y^{2}-2x+4y-6=0 \\ \\ \bold{5)} \ 2x^{2}+2y^{2}-24x-16y-8=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 2, \ the \ equation \ becomes: \\ x^{2}+y^{2}-12x-8y-4=0

\bold{6)} \ x^{2}+y^{2}+2x-12y

So let's match each equation:

\bold{From \ a)} \\ \\ (h,k)=(6,4),\ r=2\sqrt{14} \\ D=-12, \ E=-8 \\ F=-4

Then, its general form is:

x^{2}+y^{2}-12x-8y-4=0

<em><u>First. a) matches 5) </u></em>

\bold{From \ b)} \\ \\ (h,k)=(2,-6),\ r=2\sqrt{15} \\ D=-4, \ E=12 \\ F=-20

Then, its general form is:

x^{2}+y^{2}-4x+12y-20=0

<em><u>Second. b) matches 1) </u></em>

\bold{From \ c)} \\ \\ (h,k)=(-2,-3),\ r=3\sqrt{2} \\ D=4, \ E=6 \\ F=-5

Then, its general form is:

x^{2}+y^{2}+4x+6y-5=0

<em><u>Third. c) matches 3)</u></em>

\bold{From \ d)} \\ \\ (h,k)=(-1,6),\ r=\sqrt{46} \\ D=2, \ E=-12, \ F=-9

Then, its general form is: x^{2}+y^{2}+2x-12y-9=0

<em><u>Fourth. d) matches 6)</u></em>
6 0
3 years ago
Read 2 more answers
help. If 20 men can survive for 24 days on 15 cans of rations, how many cans will be needed for 16 men to survive for 36 days?
Semmy [17]

Answer: 29 cans.

Step-by-step explanation:

20 can survive 24 days with 15 cans.

If X is the number of days that a man can survive with one can of rations.

so X is in the units can/day

then we have that:

24/15*X = 20

X = 20*15/24 = 12.5

This means that a man can live 12.5 days with a can of food.

then, for 16 men and 36 days we have:

(36/C)*12.5 = 16

C = (36/16)*12.5 = 28.1215

And we can not have a 0.1215 of a can, so we should round it up to 29 cans.

4 0
2 years ago
Write 4y−10=0 in slope-intercept form
pogonyaev

Answer:

y=5/2

Step-by-step explanation:

4 0
3 years ago
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There are 10soccer teams in the S-league. Each team plays one match against each of the other teams. How many matches will be pl
ipn [44]
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45 matches in all >.< :)
8 0
3 years ago
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