Answer:
a.
Explanation:
The Windows Group Policy feature provides a centralized set of rules that govern the way Windows operates in enterprise environments. The Windows Group Policy is found in every single Microsoft Windows operating system, and fully controls the working environment of user accounts and computer accounts. This feature allows the user to manually make restrictions and changes such as blocking access to certain sections of the Windows control panel or setting a specific website as the home page for every account on the network.
Answer:
App that reminds you to drink water
Explanation:
A lot of people are dehydrated because they don't remeber to drink water
Answer:
The answer is "compromise"
Explanation:
In computer science, the comprised system is used to describe as any technological resource, that has been negatively affected by an untrustworthy source for nondisclosure, integrity or accessibility either deliberately or inadvertently.
- In this, the mechanical interaction from the unauthorized source or technological progress can result in compromise.
- This helps you and the partner to meet each other's interests by taking into consideration both the positions and the solution to the main problem.
Answer:
7
Explanation:
Because the q.length is a inbuilt function in the programming which used to get the length of the array. In the array, there are 7 values are store. Therefore, the size 7 store in the variable z.
For example:
int[] array={1,2};
int x = array.length;
the answer of above code is 2, because the elements present in the array is 2.
Answer:
Two systems are connected by a router. Both systems and the router have transmission rates of 1,000bps. Each link has a propagation delay of 10ms. Also, it takes router 2ms in order to process the packet (e.g. decide where to forward it). Suppose the first system wants to send a 10,000 bit packet to the second system. How long will it take before receiver system receives the entire packet.
Transmission time for first Router = 10,000 bits / 1000 bps = 10 seconds
Receiving time for seond route r= 10,000 bits / 1000 bps = 10 seconds
Propagation delay = 10ms = .01 seconds x 2 for two delays = .02 seconds
First router 2ms to process = .002 seconds
Add all the times together and we get 20.022 seconds which is the same as or 20 seconds and 22 ms
