As we know that 10-bAse data travels at the rate of 10 mbps,
therefore at 1 sec we have 10240 bytes.
We have to calculate for 64 bytes travelling in one second.
Multiply both sides by 64.
64 sec = 10240 x 64 bytes
64 bytes = 64 / 10240 sec
Now we have to calculate for light of speed
1 sec = 186000 miles
Substitute this value to the formula above
64 bytes = 64 / 10240 x 1 sec = 64 / 10240 x 186000 miles =
64 / 10240 x 186000 x 5280 feet = 6138x10^3 feet
Therefore, 64 bytes is equal to 6138 x 10^3 feet long
message
Answer: True
Explanation: But it depends on two factors that's the problem and the experience of the computer user support
Um I need a image or smth
The answer is the second answer Increasing the size of the wire.
Answer:200 MBps
Explanation: Fibre channel are those channel that work with the data transfer protocol at the rate of high speed.They work on the connection that are based on the links and loops or share any other form of point to point connection.
It is measured that theoretically the speed of the dual looped FC is supposed to be 200 MBps rate having the two loop form connection.
