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Ksenya-84 [330]
3 years ago
12

Please help me:(I’ll give you the brainliest

Mathematics
1 answer:
Savatey [412]3 years ago
4 0

Answer:

The range of values for x is; 5 < x < 29

Step-by-step explanation:

The given parameters are;

\overline {AB} = 15

\overline {AD} = 18

\overline {BC} = \overline {CD} Given

\overline {AC} = \overline {AC} by reflexive property

∠BCA = 2·x - 10

∠DCA = 48°

Since 15 < 18, given the common sides of the tringle ΔABC and triangle ΔADC, angle ∡(2·x - 10)° < 48°

Therefore;

2x - 10 < 48

2·x < 48 + 10

∴ x < 29

Also, given that 2·x - 10 is real, 0 < 2·x - 10

10 < 2·x

10/2 < x

5 < x

Therefore, an acceptable range is 5 < x < 29

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Step-by-step explanation:

Use proportions to solve:

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3 years ago
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Svetllana [295]

Answer:

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Step-by-step explanation:

We are asked to find the tangent line approximation for f(x)=\sqrt{10+x} near x=0.

We will use linear approximation formula for a tangent line L(x) of a function f(x) at x=a to solve our given problem.

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Now, we will find derivative of given function as:

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Therefore, our required tangent line for approximation would be L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x.

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artcher [175]

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Step-by-step explanation:

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Step-by-step explanation:

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