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Travka [436]
3 years ago
13

PLEASE HELP URGENT!!! 90 POINTS

Mathematics
1 answer:
Lina20 [59]3 years ago
4 0

\Given :

x^{3} +x^{2} -20x

Solution:

x^{3} +x^{2} -20x

taking x common from the given polynomial

⇒x(x^{2} +x-20)=0

⇒x(x(x+5)-4(x+5))=0

⇒x(x+5)(x-4)=0

⇒ x=0 , x+5=0 , x-4=0

⇒x = 0 , x = -5 , x = 4

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you are rolling a 10-sided die with sides numbered 1-10. you keep rolling the die until you roll a prime number and then stop. l
evablogger [386]

The formula for E(x) would be SUM[ X(n)P(n)] from n = 1 to n = infinity until we get the prime number

In the given problem, a 10-sided die with 1-10 numbers is rolled until we get a prime number

Prime numbers between 1-10 = 2,3,5,7 (4 prime numbers)

Non - prime numbers = 1,4,6,8,9,10( 6 non-prime number)

Let X be the number of times the die is rolled

The probability of getting a prime =

P(Prime) = \frac{4}{10}

Now, the value of

E(X)=∑x.P(x) [ x-> {1, infinity}]

= P(1)X(1) +P(2)X(2)+P(3)X(3)+P(4)X(4)........+ P(n)X(n)

= 1.\frac{4}{10} + 2. \frac{6}{10}.\frac{4}{10} + 3.\frac{6}{10}.\frac{6}{10}\frac{4}{10} + 4. \frac{6}{10}.\frac{6}{10}.\frac{6}{10}.\frac{4}{10}.......

Hence, this is the value of E(x)

To learn more about Prime number, here

brainly.com/question/9315685

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2 years ago
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svp [43]

Answer:

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Step-by-step explanation:

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