Answer: 11,440 ft change in altitude
Step-by-step explanation: To do this equation, you first need to find a positive number that is high enough to reach positive 11,100. Because we are not starting at zero on the number line and are instead starting at negative 340, the number will be a little higher than 11,100. The simplest way to find the answer is by changing negative 340 to a positive value and adding it to positive 11,100. This should equal 11,440 To prove this, grab a calculator and add 11,440 to negative 340. To make 340 a negative integer, type in that number and then click the button that looks like this, +/_ Once you have added 11,440 to negative 340, the sum of the two integers should pop up as 11,100 on your calculator. The final and correct answer is equivalent to a 11,440-foot change in altitude.
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Area = (base times height) / 2
Can rewrite it as
A= b * h * 1/2
16 = (x^(1/3)) * ( x^(1/2)) * (1/2))
Multiply by 2 to simplify
32 = x^(1/3) * x^(1/2)
32=x ^(5/6)
X=64
Base = 4
Height = 8
Please look below at how you multiply variables that have fractions as exponents (you need to add the exponents, common denominator and all that)
In order to find the scale they are using first you must divide 12 by 3.75.
But since we get to estimate, the 3.75 will be made into a 4 because it's the whole number closest to 3.75.
12/4=3
Take your 3 inch scale and multiply it by 3 (we are using 3 instead of 2.8 because it's a whole number) to get the real life fence size.
3x3=9
The fence is about 9 feet.
Answer:
70
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20
Step-by-step explanation:
mark me as brilliant
Answer:

Step-by-step explanation:
The equation for the monthly charge has the following format

In which y(x) is the cost in function of the number of kilowatt-hours used(x), a is the price of each killowatt hour and b is the fixed(base) charge.
Base charge of $17.32 per month.
This means that 
charge of 7.32 cents per kilowatt-hour
Our answer is in dollars. Each dollar is 100 cents. So 7.32 cents is 
Write an equation for the monthly charge y in terms of x, the number of kilowatt-hours used.

