Answer:
33,750,000 pounds of animals were processed during 5 days.
Step-by-step explanation:
If the average animal weight is 1350 lbs and 5,000 beef are slaughtered in one day, the total amount for one day would be: (1350)(5000) = 6,750,000 lbs.
Now we need to multiply this number by five since we want to know the total of pounds of animals processed during 5 days.
6,750,000 (5) = 33,750,000 pounds of animals.
There are two c's. You must pay attention to capitalization, there's a lowercase c and an uppercase C which represent two different variables. Also, the W is capitalized which could make your answer incorrect if you don't use the same notation.
Solving for small c..

So it's the answer shown in the picture, but it should be a capital W instead of a lowercase w.
Hi I am here to help :). I think the answer would be 7/4. Good luck!
So add them together
100+132.5=232.5 kg
kilograms=1000 grams so
232.5kg=1000 times 232.5 grams
232500 grams