Question

Calculate the molarity of a potassium hydroxide solution if 25.0 ml of this solution was completely neutralized by 23.3 ml of 0.506 M sulfuric acid.

Answer 1

Answer: 0.943 M of potassium hydroxide solution is required.

Explanation:

A neutralization reaction is defined as the reaction in which an acid reacts with a base to form a salt and water molecule.

To calculate the molarity of potassium hydroxide, the equation used is:

$n_1M_1V_1=n_2M_2V_2$              ........(1)

where,

$n_1, M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid that is $H_2SO_4$

$n_2, M_2\text{ and }V_2$ are the n-factor, molarity and volume of the base that is KOH

We are given:

$n_1=2\\M_1=0.506M\\V_1=23.3mL\\n_2=1\\M_2=?M\\V_2=25.0mL$

Putting values in equation 1, we get:

$2\times 0.506\times 23.3=1\times M_2\times 25.0\\\\M_2=\frac{2\times 0.506\times 23.3}{1\times 25.0}\\\\M_2=0.943M$

Hence, 0.943 M of potassium hydroxide solution is required.