K. Ionization energy increases as you go up and to the right, and k is the furthest left and furthest down
Answer:
0.404 moles Na⁺ and 0.404 moles Cl⁻
Explanation:
In the solution you have 23.6g of NaCl. As molar mass of NaCl is 58.44g/mol. Moles you have present are:
23.6g NaCl × (1mol / 58.44g) = <em>0.404 moles of NaCl</em>
As you can see in the formula, each mole of NaCl contains 1 mole of Na⁺ and 1 mole of Cl⁻. Thus, moles of each ion are:
<em>0.404 moles Na⁺ and 0.404 moles Cl⁻</em>
The full question is shown in the image attached to this answer
Answer:
6.2 * 10^-3
Explanation:
The reaction at equilibrium is as follows;
TiCl4(l) → Ti(s)+ 2Cl2(g)
We have to obtain the concentration of chlorine gas as follows;
[Cl2] = 1.08/70.91 g/mol × 5.2 L
[Cl2] = 0.079 M
Kc = [Cl2]^2
Kc = [ 0.079]^2
Kc = 6.2 * 10^-3
Step 1:
Write molecular Formula,
Na₅P₃O₁₀
Step 2:
Assign Oxidation number to Na (which is +1) and O (which is -2), and X (unknown) for P.
(+1)₅ + (X)₃ + (-2)₁₀ = 0
Zero means overall charge on molecule is zero (Neutral).
Step 3:
Now solve for X,
(+5) + (X ÷ 3) + (-20) = 0
X ÷ 3 = -5 + 20
X ÷ 3 = +15
X = +15 ÷ 3
X = +5
Result:
Oxidation number of P is +5.
Answer:
The number of protons you welcome
Explanation:
