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3 years ago

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Chicos estoy en un aprieto ayudarme pls Sabiendo que una falda es 5 € más cara que una blusa y que si compro 6 faldas y 4 blusas

pago 480 €, ¿cuánto vale la falda?

1 answer:

poizon [28]3 years ago

7 0

Answer:

El precio de la falda es 50 €.

Step-by-step explanation:

Lo que sabemos:

$F = 5 + B$ (1)

En donde F es por falda y B por blusa.

Si compras 6 faldas y 4 blusas y pagas 480 €:

$6F + 4B = 480$ (2)

Entonces, al introducir la ecuación (1) en (2) podemos hallar el precio de cada falda.

$6F + 4B = 480$

$6(5 + B) + 4B = 480$

$10B = 480 - 30$

$B = \frac{450}{10} = 45$

Finalmente, el precio de la falda se puede encontar con la ecuación (1):

$F = 5 + 45 = 50$

Por lo tanto, el precio de la falda es 50 €.

Espero que te sea de utilidad!

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A graphing calculator is recommended. A function is given. g(x) = x4 − 5x3 − 14x2 (a) Find all the local maximum and minimum val

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Answer:

The local maximum and minimum values are:

Local maximum

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Local minima

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Step-by-step explanation:

Let be $g(x) = x^{4}-5\cdot x^{3}-14\cdot x^{2}$ . The determination of maxima and minima is done by using the First and Second Derivatives of the Function (First and Second Derivative Tests). First, the function can be rewritten algebraically as follows:

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Then, first and second derivatives of the function are, respectively:

First derivative

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Now, let equalize the first derivative to solve and solve the resulting equation:

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$x\cdot (x-5.118)\cdot (x+1.368) = 0$

The critical points are 0, 5.118 and -1.368.

Each critical point is evaluated at the second derivative expression:

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$g''(0) = 12\cdot (0)^{2}-30\cdot (0) -28$

$g''(0) = -28$

This value leads to a local maximum.

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$g''(5.118) = 12\cdot (5.118)^{2}-30\cdot (5.118) -28$

$g''(5.118) = 132.787$

This value leads to a local minimum.

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$g''(-1.368) = 12\cdot (-1.368)^{2}-30\cdot (-1.368) -28$

$g''(-1.368) = 35.497$

This value leads to a local minimum.

Therefore, the local maximum and minimum values are:

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$g(0) = 0$

Local minima

$g(5.118) = (5.118)^{4}-5\cdot (5.118)^{3}-14\cdot (5.118)^{2}$

$g(5.118) = -350.90$

$g(-1.368) = (-1.368)^{4}-5\cdot (-1.368)^{3}-14\cdot (-1.368)^{2}$

$g(-1.368) = -9.90$

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Step-by-step explanation:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters. If your teacher just wants one, it would be the middle one. (I assume they’ll want all three, since the letters just name points, not angles.)

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B) Exterior AngleS: EAO, BOC and AOD

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2) A) Name of triangle: ABC

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