Answer:
See explanation and image attached
Explanation:
The reaction of (R)-2-chloro-3-methylbutane with potassium tert-butoxide yields a monosubstituted alkene .
Since the base is bulky, the Hoffman product predominates because attack occurs at the less hindered carbon atom to yield the major product as shown.
The alkene reacts with HBr at the secondary carbon atom to yield a carbocation intermediate which is flat and planar. Attack on either face of the carbocation yields a racemic mixture of the (2R) and (2S) products.
Rearrangement of the carbocation to yield a tertiary carbocation gives the 2-bromo-2-methyl butane product as shown in the image attached.
Answer:
B
Explanation:
In order for any conduction to take place it needs to go through a solid. Therefore it cannot travel through empty space
I believe it is a(n) independent variable
i could be wrong sorry<span />
Answer:
c
Explanation:
because the left side of reactant is take more time to make a product than the first
The reaction is:
Cr₃⁺ +3 C₁₀H₈N₂ → [Cr(C₁₀H₈N₂)₃]³⁺
2,2\'-bipyridine is bidentate ligand and neutral. It exhibits two N terminal, thus, it functions as bidentate ligand.
Therefore, three 2,2\'-bipyridine ligand fulfills the six coordination number of Cr₃⁺.
The formula for the complex is [Cr(C₁₀H₈N₂)₃]³⁺