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irga5000 [103]
3 years ago
10

A rectangle has vertices E(-4, 8), F(2, 8), G(2, -2) and H(-4, -2). The rectangle is dilated with the origin as the center of di

lation so that G' is located at (5, -5). Which algebraic representation represents this dilation?
Mathematics
1 answer:
Marizza181 [45]3 years ago
5 0

Answer:

The dilation on any point of the rectangle is P'(x,y) = \frac{5}{2}\cdot P(x,y).

Step-by-step explanation:

From Linear Algebra, we define the dilation of a point by means of the following definition:

G'(x,y) = O(x,y) +k\cdot [G(x,y)-O(x,y)] (1)

Where:

G(x,y) - Coordinates of the point G, dimensionless.

O(x,y) - Center of dilation, dimensionless.

k - Scale factor, dimensionless.

G'(x,y) - Coordinates of the point G', dimensionless.

If we know that O(x,y) = (0,0), G(x,y) =(2,-2) and G'(x,y) =(5,-5), then scale factor is:

(5,-5) = (0,0) +k\cdot [(2,-2)-(0,0)]

(5,-5) = (2\cdot k, -2\cdot k)

k = \frac{5}{2}

The dilation on any point of the rectangle is:

P'(x,y) = (0,0) + \frac{5}{2}\cdot [P(x,y)-(0,0)]

P'(x,y) = \frac{5}{2}\cdot P(x,y) (2)

The dilation on any point of the rectangle is P'(x,y) = \frac{5}{2}\cdot P(x,y).

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3 years ago
angelo's mother put $50 on a lunch card he spends the same amount each day for lunch. what is the constant rate of change for th
Rina8888 [55]

Given that Angelo spends the same amount everyday from the amount in

the lunch card, the function of the amount remaining is a linear function.

  • The constant rate of change of the function is; <u>-5.25</u>
  • The two ordered pair used to find the constant rate of change are; <u>(1, 44.75) and (2, 39.5)</u>

Reasons:

The amount Angelo's mother put on the lunch card = $50

A possible table of values to the question is presented as follows;

\begin{tabular}{r|c|c|c|c|}Days&0&1&2&3\\Money Remaining&&44.75&39.5&\end{array}\right]

Required:

The constant rate of the function that gives the amount remaining from the

amount Angelo's mother put on his lunch card.

Solution:

  • Slope \ or \ constant \ rate \ of \ change  = \mathbf{\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}

The two ordered pair that can be used to find the slope or constant rate of change are;

(x₁, y₁) = (1, 44.75), and (x₂, y₂) = (2, 39.5)

With the above two ordered pairs, we have the constant rate of change of the function given as follows;

Constant \ rate \ of \ change\  (The \ slope) =\dfrac{39.5-44.75}{2-1} = \mathbf{ -5.25}

The constant rate of change for the function that gives the amount remaining in the lunch card is; <u>-5.25</u>

Learn more about the constant rate of change of a function here:

brainly.com/question/10007759

brainly.com/question/16644839

3 0
2 years ago
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olga55 [171]
This is how I would do it:
-8x=28-4y divide the entire equation by 4
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y=7-2x.
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