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Mathematics

1 answer:

o-na [289]4 years ago

8 0

Answer:

Step-by-step explanation:

-The length of the cubes side is (x-5) and the total surface area is 1944 sq units.

-We apply the formula for surface area and equate to solve for x:

$A=6s^2\\\\1944=6(x-5)^2\\\\324=(x-5)^2\\\\324=x^2-10x+25$

#Equate to zero as below:

$324=x^2-10x+25\\\\x^2-10x+25-324=0\\\\x^2-10x-299=0\\\\\# Quadratic \ Formula:\\\\x_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\=\frac{10\pm\sqrt{(-10)^2-4(1\times-299)}}{2\times1}\\\\x_1=23, \ \ \ x_2=-13$

length dimensions are always positive.

Hence, the value of x is 23

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Use the given graph to determine the limit, if it exists. (4 points)

skelet666 [1.2K]

<h3>Answer: 3</h3>

Explanation:

Refer to the graph below. It should be similar to what your teacher gave you, based off the description.

Since we're approaching 3 from the right side, this means we'll be working with the horizontal line portion. We could start at something like x = 3.2 and move closer to 3 by getting to x = 3.1 then x = 3.01 then x = 3.001 and so on. We never actually get to 3 itself.

As x gets closer to 3 from this direction, the y values are approaching 3 since every point on this horizontal line has the same y coordinate. Technically the y value is already at 3, but it's the same idea.

In terms of notation, we can write $\displaystyle \lim_{x\to3^{+}}f(x) = 3$