Given that E is a point between Point D and F, the numerical value of segment DE is 46.
<h3>What is the numerical value of DE?</h3>
Given the data in the question;
- E is a point between point D and F.
- Segment DF = 78
- Segment DE = 5x - 9
- Segment EF = 2x + 10
- Numerical value of DE = ?
Since E is a point between point D and F.
Segment DF = Segment DE + Segment EF
78 = 5x - 9 + 2x + 10
78 = 7x + 1
7x = 78 - 1
7x = 77
x = 77/7
x = 11
Hence,
Segment DE = 5x - 9
Segment DE = 5(11) - 9
Segment DE = 55 - 9
Segment DE = 46
Given that E is a point between Point D and F, the numerical value of segment DE is 46.
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Answer:
y = 7 and x =3
Step-by-step explanation:
use elimination method
so we gonna eliminate y first
9x = 1 - 4y
-7x = -7 + 4y
7| 9x = 1 - 4y
9| -7x = -7 + 4y
63x = 7 - 28y
-63x = -63 + 36y
add eqtn 1 to eqtn2
you will get
0 = -56 + 8y
56 = -56 + 56 + 8y
56 = 8y
56÷8 = 8y÷ 8
7 = y
also eliminate x as we have done wth y
4| 9x = 1 - 4y
4| -7x = -7 + 4y
36x = 4 - 16y
-28x = -28 + 16y
add the two equations
u will get
8x = -24 + 0
8x = -24
8x÷8 = 24÷ 8
x = 3
Answer:
1.7636981 = 1.7
Step-by-step explanation:
Hope it helps :)
pls mark brainliest :P
Answer:
The piecewise function is:

Step-by-step explanation:
A piecewise function is a function that is defined in multiple intervals.
In the first interval:

The problem states that a taxi company charges $4.00 for the first mile (or part of a mile).
x is the number of miles. So
If
.
Second interval:

Here, the cost is defined by a linear function in the following format:

In which
is the initial price and r is the price paid per mile.
The problem states that each succeeding tenth of a mile costs 80 cents. So
we have the following rule of three.
1 mile - r dollars
0.1miles - 0.8 dollars



So, we have

Piecewise function:
The piecewise function is:
