Answer:
5.385
Step-by-step explanation:
We are given that the room is 3 meters in length, 4 meters in width, and a height of 2 meters.
To start with, we would need to use the Pythagorean Theorem to get the diagonal length of the box floor. The height doesn't matter here, at least not yet.
Using Pythagoras and considering the width and length, we have
3² + 4² = c²
9 + 16 = c²
25 = c²
c = 5
This is the diagonal length of the floor. Again, we create a whole new triangle making use of the height, the diagonal of the floor, and the distance we need. So we have
5² + 2² = c²
25 + 4 = c²
29 = c²
c = √29
c = 5.385 m
Thus, the needed distance is 5.385 m
