Question

Determine the intercepts of the line. -5x-4y=10

Answer 1

Answer:

$x-intercept:(-2,0)\\\\y-intercept:(0,-\frac{5}{2})$

Step-by-step explanation:

The y-intercept is where x is 0 (0,y)

The x-intercept is where y is 0 (x,0)

Insert 0 as the value for x to find the corresponding y value:

$-5(0)-4y=10$

Simplify multiplication:

$0-4y=10\\\\-4y=10$

Isolate the variable. Divide both sides by 4:

$\frac{-4y}{4}=\frac{10}{4} \\\\-y=\frac{10}{4} \\\\-y=\frac{5}{2}$

Make the variable positive. Multiply both sides by -1:

$-1(-y)=-1(\frac{5}{2})\\\\y=-\frac{5}{2}$

The y-intercept is at $(0,-\frac{5}{2})$.

Insert 0 as the value for y to determine the value of x:

$-5x-4(0)=10$

Simplify multiplication:

$-5x-0=10\\\\-5x=10$

Isolate x. Divide both sides by 5:

$\frac{-5x}{5} =\frac{10}{5} \\\\-x=2$

Multiply both sides by -1:

$-1(-x)=-1(2)\\\\x=-2$

The x-intercept is at $(-2,0)$.

:Done