Answer:
1: D
2: B
3: y=-4x+22
4: y=-8x+26
Step-by-step explanation:
1: Parallel lines have the same slope, and the only one with a slope of 3x is D
2: Perpendicular lines have an opposite slope, so a line with a slope of -1/2 would be 2, so you just flip the number and add or take away a negative sign, depending on the original slope
3: Like I said before, perpendicular lines have an opposite slope, so the slope would be -4. After you've figured that out, you just plug in the numbers given to you (and remember, x is first, y is last)
Plug in: 6=-4(4)+b
You would then solve for b.
6=-16+b
22=b
Then plug that into y=mx+b, with m being the slope (-4) and b being the y intercept (22)
4: The process for finding parallel and perpendicular lines is very similar, except you don't have to change the slope.
Plug in: 10=-8(2)-b
10=-16+b
26=b
Again, plug that into the equation y=mx+b
Hope I could be of help! Sorry if it doesn't make sense, this is my first time on this website.
Answer:
-5/9
Step-by-step explanation:
also for this one, you have to put x as 3, y as 4, and z as 1
4/3(3)-1
=4/9-1
=4/9-9/9
=-5/9
hope this helps xD
Okay and what is the question you are asking?
Answer:
Step-by-step explanation:
A geometric mean is just ![\sqrt[n]{term one * term two * term three * etc.}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bterm%20one%20%2A%20term%20two%20%2A%20term%20three%20%2A%20etc.%7D)
, where n is the number of terms.
i.e. Geometric mean of 5, 6, 7: there are three values, so the mean is ![\sqrt[3]{5*6*7}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%2A6%2A7%7D)
Answer:
Step-by-step explanation:
Given
--- acceleration
--- final velocity
--- initial velocity (it is 0, because the car starts from rest)
Required
Determine the time taken
This will be solved using Newton's first equation of motion:
Substitute values for v, u and a
Make t the subject
<em>Hence, the time taken is approximately 5.2 seconds</em>
