Answer:
quantity a is halfed
Corrected question;
A quantity a varies inversely as a quantity b, if, when b changes a changes in the inverse ratio. What happens to the quantity a if the quantity b doubles?
Step-by-step explanation:
Analysing the question;
A quantity a varies inversely as a quantity b,
a ∝ 1/b
a = k/b ......1
when b changes a changes in the inverse ratio;
Since the change at the same ratio but inversely, k = 1
So, equation 1 becomes;
a = 1/b
If the quantity b doubles,
ab = 1
a1b1 = a2b2
When b doubles, b2 = 2b1
a1b1 = a2(2b1)
Making a2 the subject of formula;
a2 = a1b1/(2b1)
a2 = a1/2
Therefore, when b doubles, a will be divided by 2, that means a is halfed.
Answer:
prop they're constant inchangeb
Step-by-step explanation:
Answer:
Y = 4/3x + 0
Step-by-step explanation:
(-3,-4) and (3,4) can be plugged in to rise over run.
y 4 -(-4) = 8
x 3 - (-3) = 6
8/6 = 4/3
Plug into slope intercept form
4 = 4/3(3) + b
4 = 12/3 +b
4 = 4 +b
Subtract from both sides
0 = b
Y = 4/3x + 0
