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Vadim26 [7]
3 years ago
13

What is slope 1 and 2? ​

Mathematics
2 answers:
Mila [183]3 years ago
6 0

Answer:

Lets calculate the slope of the line 'l'

Slope is rise over run of a line, so we will see how much the y of the line changes by changing x by 1

So, basically we will select a point on the line and see how much the y-value increases for the point rightward to our point

we see that the y increased by 1 and hence, its slope is 1

Now, the slope of line 'k'

again, we will select a point and go one point to the right

here, we see that the y increases by 2

therefore the slope of line 'k' is 2

Veseljchak [2.6K]3 years ago
6 0
Slope of e is 1
slope of k is 2

you go up one and right one on "e", 1 / 1 is 1.
you go up two and right one on "k", 2 / 1 is 2.
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the length of a rectangle is 5 times as long as its breadth and its area is 1620 m² find area of square whose perimeter is equal
Rus_ich [418]

Answer:

Area of the square is 2916 m^{2}.

Step-by-step explanation:

Let the breadth of the rectangle be represented by w. So that;

length of rectangle = 5w

Area of rectangle = length x breadth

                             = 5w x w

1620 = 5w^{2}

divide through by 5 to have,

w^{2} = 324

w = \sqrt{324}

   = 18

Thus, the breadth of the rectangle is 18 m.

length = 5 w = 5 x 18

           = 90 m

The length of the rectangle is 90 m.

Perimeter of the rectangle = 2(l + w)

                                  = 2( 90 + 18)

                                  = 216 m

Perimeter of a square = 4l

where l is the length of its side.

Given that the perimeters of the rectangle and square are equal, then;

4l = 216

l = \frac{216}{4}

 = 54

length of the side of square is 54 m.

Therefore,

Area of square = l^{2}

                         = 54^{2}

                        = 2916

Area of the square whose perimeter is equal to that of the rectangle is 2916 m^{2}.

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