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ss7ja [257]
3 years ago
9

How would I multiply 43.7(1.23) step by step

Mathematics
1 answer:
DochEvi [55]3 years ago
8 0
4370
123
———
13110
+87400
437000
————
537510

Then you add the number of space the coma takes in the two numbers, so 2+1=3 and u put it in the third place so the answer is : 53,751
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Please help will mark you Brainliest
Alina [70]

Answer:11

Step-by-step explanation:Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    3*(x-5)-(18)=0  

Step by step solution :

STEP

1

:

Equation at the end of step 1

 3 • (x - 5) -  18  = 0  

STEP

2

:

STEP

3

:

Pulling out like terms

3.1     Pull out like factors :

  3x - 33  =   3 • (x - 11)  

Equation at the end of step

3

:

 3 • (x - 11)  = 0  

STEP

4

:

Equations which are never true:

4.1      Solve :    3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

4.2      Solve  :    x-11 = 0  

Add  11  to both sides of the equation :  

                     x = 11

One solution was found :

x = 11

8 0
3 years ago
Help please? its an exam
Nikolay [14]

Answer:

TU=4

Step-by-step explanation:

WU cuts the triangle in half (hint- angleTUW=90°)

so VU=TU

therefore, TU=4

5 0
3 years ago
in an election they are four canadates j k l and m Teri is drawing a pie chart to show the results the sector for j and k have b
gizmo_the_mogwai [7]

Answer:

2+2=4

Step-by-step explanation:

8 0
3 years ago
Find the absolute minimum and absolute maximum values of f on the given interval. f(x) = (x2 − 1)3, [−1, 2]
Alja [10]

Given :

F(x)=3(x^2-1)

To Find :

the absolute minimum and absolute maximum values of f on the given interval

[-1,2] .

Solution :

Now , getting first order differential equation and equating its equal to zero.

\dfrac{d(3x^2-3)}{dx}=0\\\\6x=0\\x=0

So , x=0 is critical point .

Now , coefficient of x^2 is positive .

Therefore , it is increasing function after  x=0 .

So , min value will be at , x=0.

Min = (0^2-1)\times 3=-3

And maximum value will be the maximum at the x=2 because it is increasing function .

Max=(2^2-1)\times 3=9

Therefore , max and min value is 9 and -3 respectively .

Hence , this is the required solution .

3 0
3 years ago
Please help!!
polet [3.4K]

Answer:

The absolute value of the quadratic term,  \left | -\dfrac{1}{2}   \right | is less than 1

Step-by-step explanation:

The given function is y = (-1/2)·x² - 7

The parent function is y = x²

The vertical compression or stretching of a quadratic function is given by the value of the coefficient, <em>a</em>, of the quadratic term, x² of a quadratic function, a·x²

A quadratic function is vertically compressed if the coefficient, \left | a  \right | < 1.

In the given function, y = (-1/2)·x² - 7, the absolute value of the coefficient of the quadratic term, \left | -\dfrac{1}{2}   \right | < 1, therefore, the equation, y = (-1/2)·x² - 7, will be vertically compressed compared to the parent function, y = x².

6 0
3 years ago
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