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omeli [17]
3 years ago
11

If a^b=x, what is a^(b+2)?

Mathematics
1 answer:
prisoha [69]3 years ago
3 0
\bf \boxed{a^b=x}\implies \sqrt[b]{a^b}=\sqrt[b]{x}\implies \boxed{a=\sqrt[b]{x}}\\\\
-------------------------------\\\\
a^{b+2}\implies a^b\cdot  a^2\implies \boxed{x}\cdot \left( \boxed{\sqrt[b]{x}} \right)^2\implies x\cdot \sqrt[b]{x^2}\implies x\sqrt[b]{x^2}
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La frase lingüística "cuatro veces un número dividido por la suma de dos
polet [3.4K]

Answer:

Las opciones no se pueden ver, así que responderé de una forma general.

Primero rompamos la frase en partes más cortas

"cuatro veces un número..."

Esto se escribe como 4*N, donde N es el número.

"... la suma de dos

números"

Esto se escribe como K + M

donde K y M son dos números, entonces K + M es la suma de dos números.

Entonces:

"cuatro veces un número dividido por la suma de dos

números"

Se escribirá como:

(4*N)/(K + M )

8 0
3 years ago
Does this table represent a linear equation?
olga2289 [7]
No it does not
Hope this helps
5 0
2 years ago
Andre wrote the expression -2 + 4x = 3 to represent the relationship
ankoles [38]

Answer:

4x -2 = 3    and 4x + -2 = 3

Step-by-step explanation:

-2 + 4x = 3 ---- 4x -2 = 3   ------------ 4x + -2 = 3

                            +2  +2                        - 2  +2

                     ------------------              ----------------        

                          4x = 5                         4x = 5

                          ----   ----                      -----  -----

                           4      4                         4      4

                  x = 1.25 or 1  1/4               x = 1.25 or 1  1/4

7 0
2 years ago
Question B,C and D I need answers to these parts.
Alik [6]
Explanation<h2>Part b</h2>

So in part (b) we must give the annual growth factor. For any quantity that increases annualy, this factor is the number by which the quantity multiplies itself every year. For a given quantity that increases at a rate of p% its growth factor is given by:

1+\frac{p}{100}

In this case the production of ethanol increases at a rate of 5.5% per year which means that the growth factor is:

1+\frac{5.5}{100}=1.055

Then the growth factor and answer to part (b) is 1.055.

In part (c) we must write an equation that models the increase in the ethanol production. Given an initial qunatity Q and an annual growth factor k the quantity after x years is given by multiplying the initial quantity by the growth factor raised to the x. Then we get:

C(x)=Q\cdot k^x

In this case we need a function for the amount of ethanol produced E, x years after 1990. The 0.9 billion gallons produced that year compose our initial quantity and knowing that the annual growth factor is 1.055 we have the desire equation:

E(x)=0.9\cdot1.055^x

And that's the answer to part (c).

In part (d) we have to compare the actual production of ethanol in 2008 to the one predicted by the equation of part (c). Remember that x represents the years passed after 1990 so for the year 2008 the value of x is given by:

x=2008-1990=18

So the number we are looking for is E(18):

E(18)=0.9\cdot1.055^{18}=2.359

So the production estimated for 2008 is 2.359 billions of gallons. Then the actual production of 9 billion gallons is higher than the one predicted by our equation.

5 0
1 year ago
Geometry question I’m confused with this help
anyanavicka [17]

Answer: ∠PQR = 130°

Step-by-step explanation:

      The word bisects means that angle PQS and SQR are equal to each other.

           3x + 5 = 2x + 25

           3x = 20

           x = 20

      Now, we will plug this value back in and solve for angle PQR. There are three ways we could do this.

      [1]

             (3x + 5) + (2x + 25)

             (3(20) + 5) + (2(20) + 25)

             (60 + 5) + (40 + 25)

             (65) + (65)

                 130 degrees

      [2]

             (3x + 5) * 2

             (3(20) + 5) * 2

             (65) * 2

                 130 degrees

      [3]

             (2x + 25) * 2

             (2(20) + 25) * 2

             (65) * 2

                 130 degrees

3 0
1 year ago
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