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Degger [83]
3 years ago
6

-2(x+1/4) +1=5 Solve for x

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
7 0

Answer:

x = -2.25

Step-by-step explanation:

-2(x+1/4)+1=5

-2x-2/4+1=5

-2x-2/4+4/4=5

-2x+2/4=5

-2x=5-2/4

-2x=20/4-2/4

-2x=18/4

-x=4.5 / 2

-x=2.25

x=-2.25

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A cell phone company charges a monthly rate of $12.95 and $0.25 a minute per call. The bill for m minutes is $21.20. Write an eq
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Answer:

y= 12.95x + 0.25

Step-by-step explanation:

4 0
3 years ago
Solve the inequality 4(n-3)- 6 > 18
Sonbull [250]

Answer:

n>9

Step-by-step explanation:

4(n-3)- 6 > 18

To solve this inequality we need to remove the parenthesis

distribute 4 inside the parenthesis

4n -12 - 6 > 18

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4n - 18 > 18

We need to isolate 'n', so we add 18 on both sides

4n > 36

Now divide both sides by 4

n > 9

So the value of n is greater than 9


8 0
3 years ago
Read 2 more answers
One cold night the temperature was 0 degrees at 8 p.m. The temperature dropped at a constant rate from 8 p.m. to midnight. At mi
aliina [53]

Answer:

- 4.2 degrees

Step-by-step explanation:

If the drop was from temp 0 at 8 pm to temp -16.8 at midnight (4 hours later)

then,the drop is given by the rate: -16.8/4 = - 4.2 degrees per hour

Therefore, at 9 pm the temperature was:

0 degrees - 4.2 degrees = - 4.2 degrees

5 0
3 years ago
Read 2 more answers
David bought a pizza for $12.74 and four medium drinks. Define a variable and write an expression to represent the total amount
SSSSS [86.1K]
You could say each drink is d. And we'll say the total is t. David got 4 drinks,

So... 12.74 + 4d = t

Hope this helps!
7 0
3 years ago
In March 2007, Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours. You wonder
Rasek [7]

Answer:

The hypotheses used in this situation

H_0:\mu = 14.6

H_a:\mu \neq 14.6

Step-by-step explanation:

We are given that  Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours.

Mean = \mu = 14.6

Claim : The amount UMSL students study is different from this 14.6 hour benchmark.

The hypotheses used in this situation

H_0:\mu = 14.6

H_a:\mu \neq 14.6

5 0
3 years ago
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