Answer:
3p³ + 2p² – 3p – 11
Step-by-step explanation:
From the question given above, the following data were obtained:
Side 1 (S₁) = –1(p + 5)
Side 2 (S₂) = 2(p² – 3)
Side 3 (S₃) = 3p³ – 2p
Perimeter (P) =?
The perimeter of the triangle can be obtained as follow
P = S₁ + S₂ + S₃
P = –1(p + 5) + 2(p² – 3) + 3p³ – 2p
Clear bracket
P = –p – 5 + 2p² – 6 + 3p³ – 2p
Rearrange
P = 3p³ + 2p² – 2p – p – 6 – 5
P = 3p³ + 2p² – 3p – 11
Therefore, the perimeter of the triangle is 3p³ + 2p² – 3p – 11
<span>200 is 3333.33333333% of 6
or 3333.3% with the line on top :)</span>
We are asked to determine the probability of having at least one digit of zero in a winning lottery number that is composed of four digits from the set of numbers from 0 to 9. To determine the probability to be known, we can approach this problem by computing for the probability by counting theory for each digit.
Digit 1: there are 10 choices, so the probability is 1/10
Digit 2: there are only9 choices, probability of 1/9
Digit 3: there are also 9 choices, probability of 1/9
Digit 4: 9 digits as 0 is not a included
*(numbers beginning with zero do not count zero as part of the number)
Hence the probability is (1/10)*(1/9)*(1/9)*(1/9) = <span>0.000137</span>
3 and 8 or -3 and -8
Use the guess/check method for this problem. Eventually you will find that the integers are 3 and 8.
3 is 5 less than 8, and 3 * 8 is 24.
Also, -3 and -8 work too.
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