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zmey [24]
3 years ago
12

8(4q-5)-7=5(5q-8) fast !!!!

Mathematics
2 answers:
Oksana_A [137]3 years ago
8 0

Answer:

8(4q-5)-7=5(5q-8)

32q - 40 - 7 = 25q - 40

32q - 25q = 40 -40 +7

7q = 7

q = 7/7

q = 1

mote1985 [20]3 years ago
8 0
28q - 40 - 7 = 25q - 40
-25q -25q
————————————
3q - 40 - 7 = 40
40 - 7 = 33

3q - 33 = 40
33 + 40 = 76
33 / 3 = 11
q = 11
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tresset_1 [31]

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and,

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8 0
3 years ago
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3 0
3 years ago
if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?
Kay [80]

Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
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In this problem:

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The desired probability is:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1)

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P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026

P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

7 0
2 years ago
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